grep找到包含“ \t" [英] grep find lines that contains " \t"

问题描述

我被要求制作一个shell脚本来检查文件中的简单错误。
我想找到每行$ if
$ b

（正则表达式:)[] \ t。/ b>

问题在于grep忽略了\并将t作为文字。我也尝试在文件中写入字符本身，并要求grep读取它，但它不起作用。
有没有办法在文件中使用任何常用的linux工具（如grep）找到正则表达式\ t？

我已经尝试过：

  grep -E --ignore-case --line-number --with-filename --file =b文件
  

（b包含：）
还有：

  grep -E --ignore-case --line-number --with-filename --regexp =[\t]file 
  

解决方案

您可以使用C风格的字符串 $'...'

  grep $'\t'file.txt 
  

或 sed ：

  sed -n'/ \ t / p'file.txt 
  

I was requested to make a shell script to check for simple mistakes in files. I wanted to find, for each line if

(regex:) "[ ]\t" ever happens.

The problem is that grep is ignoring the \ and is taking "t" as a literal. I also tried writting the characters themselves in a file and asking grep to read it but it didn't work. Is there a way to find for the regex " \t" in files using any of the usual linux tools (like grep)?

I already tried:

grep -E --ignore-case --line-number --with-filename --file="b" file

(b contains: " ") and also:

grep -E --ignore-case --line-number --with-filename --regexp=" [\t]" file

解决方案

You can use C-style string $'...'

grep $'\t' file.txt

Or sed:

sed -n '/\t/p' file.txt

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