使用shell脚本替换第二列 [英] Replacing second column using shell script

问题描述

我想将第二列更改为大写，我只想在shell脚本中执行此操作。 （没有内衬！）

I want to change the second column to upper case and I want to do it in shell script only. (no one liners!)

#!/bin/sh
# read file line by line
file="/pdump/country.000000.txt"
while read line
do
mycol=`echo $line | awk -F"," '{print $2}'`
mycol_new=`echo $mycol | tr "[:lower:]" [:upper:]`
echo $line | awk -F"," '{print $1 "," $mycol_new "," $3 "," $4 "," $5 "," $6 "," $7 "," $8}'
done < $file

我无法用$ mycol_new取代$ 2。
任何建议？

I am not able to replace the $2 with $mycol_new. Any suggestion?

推荐答案

awk 看不到 $ mycol_new ，因为它是一个shell变量。下面是使用 -v 标志将shell变量传递到awk的一种方法：

awk cannot see $mycol_new because it is a shell variable. Here is one way of passing a shell variable into awk using the -v flag:

echo $line | awk -v var="$mycol_new" -F"," '{print $1 "," var "," $3 "," $4 "," $5 "," $6 "," $7 "," $8}'

这是另一种方法，它让shell扩展 $ mycol_new ：

Here is an alternative method which lets the shell expand $mycol_new:

echo $line | awk -F"," '{print $1 ",'"$mycol_new"'," $3 "," $4 "," $5 "," $6 "," $7 "," $8}'

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