如何使用GNUMake的通配符函数排除特定文件？ [英] How to exclude a particular file with GNUMake's wildcard function?

问题描述

我的项目的目录结构如下：

  dir1_contents：= $（通配符dir1 / *）
 dir3_contents：= $（通配符dir3 / *）
 
全部：clean_dir1 clean_dir3 
 
 clean_dir1：
 echo'dir1_contents = $（dir1_contents）'
 
 clean_dir3：
 echo'dir3_contents = $（dir3_contents）'
  

当我运行make时，是我得到的：

  $ pwd 
 make-test 
 
 $ make -s 
 dir1_contents = dir1 / dir2 dir1 / file2.junk dir1 / file3.junk 
 dir3_contents = dir3 / file4.junk 
  

我想在 dir1_contents 中获取 dir1 的内容。但是我想从该列表中排除 file3.junk 。我该怎么做？

也许我应该使用 grep -v ？但我不确定这是最好的方法。

解决方案使用 $（filter- out pattern ， text ） text function

  $（过滤掉file3.junk，$ {dir1_contents}）
  

^{（有人建议使用％/ file3.junk 而不是 file3.junk ，但我相信你不会需要的;我让你去实验）}

My project's directory structure is as follows:

My Makefile looks like this:

dir1_contents := $(wildcard dir1/*) 
dir3_contents := $(wildcard dir3/*)

all: clean_dir1 clean_dir3

clean_dir1:
    echo 'dir1_contents = $(dir1_contents)'

clean_dir3:
echo 'dir3_contents = $(dir3_contents)'

When I run make, this is what I get:

$ pwd
make-test

$ make -s
dir1_contents = dir1/dir2 dir1/file2.junk dir1/file3.junk
dir3_contents = dir3/file4.junk

I want to get the contents of dir1 in dir1_contents. But I want to exclude file3.junk from that list. How can I do it?

Perhaps I should use grep -v? But I'm not sure that's the best way. Is there a built-in GNUMake function I can use here?

解决方案

Use the $(filter-out pattern, text ) text function

 $(filter-out file3.junk,${dir1_contents})

^{(someone suggested to use %/file3.junk instead of file3.junk, but I believe you don't need that; I leave you to experiment)}

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