多行，重复匹配 [英] Multiple line, repeated occurence matching

问题描述

我提到下面的问题，但有点不同。只有在efg匹配不同行时，才需要获取具有abc的行。我只需要在匹配efg前匹配最新的匹配abc行...

如何使用grep跨多行查找模式？

 等等等等.. 
等等等等.. 
等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等blah2 
等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等abc blah3 
 blah blah .. 
 blah blah .. 
 blah abc blah4 
 blah blah .. 
 blah blah blah 
 
 blah abc blah5 
等等等等.. 
等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等等。 blah blah 
 blah abc blah7 
 blah blah .. 
 blah blah .. 
 blah abc blah8 
 blah blah .. 
  

预计产量

  blah abc blah2 
 blah abc blah6 
  

这可能适用于你（GNU sed）：

  sed -n' / abc / h; / efg /！b; x; / abc / p; z; x'文件
  

<将最新的 abc 行保存在保存空间（HS）中。当遇到包含 efg 的行时，切换到HS，并且如果该行包含 abc 打印它。

I refer to below question, but with a bit difference. I need to only get line that has "abc" when there is "efg" matching at different line. And I only need the latest matched "abc" line before "efg" is matched...

How to find patterns across multiple lines using grep?

blah blah..
blah blah..
blah abc blah1
blah blah..
blah blah..
blah abc blah2
blah blah..
blah efg1 blah blah
blah efg2 blah blah
blah blah..
blah blah..

blah abc blah3
blah blah..
blah blah..
blah abc blah4
blah blah..
blah blah blah

blah abc blah5
blah blah..
blah blah..
blah abc blah6
blah blah..
blah efg3 blah blah

blah efg4 blah blah
blah abc blah7
blah blah..
blah blah..
blah abc blah8
blah blah..

Expected output

blah abc blah2
blah abc blah6

解决方案

This might work for you (GNU sed):

sed -n '/abc/h;/efg/!b;x;/abc/p;z;x' file

Store the latest abc line in the hold space (HS). When encountering a line containing efg, switch to the HS and if that line contains abc print it.

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