Matplotlib：检查网格是否打开？ [英] Matplotlib: check if grid is on?

问题描述

Matplotlib有一个非常简单的方法来切换数字上的网格线：

  from matplotlib.figure import图
 fig = figure（）
 ax = fig.add_subplot（111）
 ax.grid（True）
  

但是，它似乎没有任何方法来确定网格的状态（on / True或off / False）？

源代码揭示了隐藏在 Axis 类中的私有变量： self._gridOnMinor 和 self._gridOnMajor

访问这些可以通过以下方式完成：

  ax.xaxis._gridOnMinor 
 ax.yaxis._gridOnMinor 
  

等等......
但是因为这些被指定为私有，所以我有点担心这样做。

这是否是唯一的检查网格是打开还是关闭的方法？

解决方案

我有同样的问题，必须在我的实现一个特殊的变量CLAS要注意电网状态。所以我想你要么保持你的危险的私人方法或我的丑陋的方法：（$ / b>

Matplotlib has a very easy method for toggling gridlines on a figure:

from matplotlib.figure import Figure
fig = Figure()
ax = fig.add_subplot(111)
ax.grid(True)

But it does not seem to have any method to determine the state of the grid (on/True or off/False)?

A look at the source code reveals that buried in the Axis class, there are the private variables: self._gridOnMinor and self._gridOnMajor

Accessing these could be done by:

ax.xaxis._gridOnMinor
ax.yaxis._gridOnMinor

and so on... but as these are designated as private, I'm a bit wary about doing so.

Is this really the only way to check whether the grid is on or off?

解决方案

I had the same problems and had to implement a special variable in my class to be aware of grid state. So I guess you either stay with your "dangerous private method" or with my "ugly method" :(

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