如何使StringGrid的列适合网格的宽度？ [英] How do I make a StringGrid's columns fit the grid's width?

问题描述

我一直在寻找一个没有任何运气的解决方案。有谁知道一个简单的方法来做到这一点？我想拉伸例如我的网格的第二柱适合网格的宽度！

解决方案

使用 ColWidths 属性，如下所示：

  with StringGrid1 do 
 ColWidths [1] ：= ClientWidth  -  ColWidths [0]  -  2 * GridLineWidth; 
  

对于更强大和更灵活的解决方案，请考虑所有固定列并对列索引进行参数化：

  procedure SetColumnFullWidth（Grid：TStringGrid; ACol：Integer）; 
 var 
 I：Integer; 
 FixedWidth：Integer;如果ACol> = FixedCols，则
以Grid 
开始
然后
 begin 
 FixedWidth：= 0; 
 for I：= 0 to FixedCols  -  1 do 
 Inc（FixedWidth，ColWidths [I] + GridLineWidth）; 
 ColWidths [ACol]：= ClientWidth  -  FixedWidth  -  GridLineWidth; 
 end; 
 end; 
 
程序TForm1.Button1Click（发件人：TObject）; 
 begin 
 SetColumnFullWidth（StringGrid1，4）; 
 end; 
  

I've been looking for a long time for a solution without any luck. Does anyone know a simple way to do that? I would like to stretch for example the second colum of my grid to fit the grid's width!

解决方案

Use the ColWidths property, like so:

with StringGrid1 do
  ColWidths[1] := ClientWidth - ColWidths[0] - 2 * GridLineWidth;

And for a more robust and flexible solution, take all fixed columns into account and parameterize the column index:

procedure SetColumnFullWidth(Grid: TStringGrid; ACol: Integer);
var
  I: Integer;
  FixedWidth: Integer;
begin
  with Grid do
    if ACol >= FixedCols then
    begin
      FixedWidth := 0;
      for I := 0 to FixedCols - 1 do
        Inc(FixedWidth, ColWidths[I] + GridLineWidth);
      ColWidths[ACol] := ClientWidth - FixedWidth - GridLineWidth;
    end;
end;

procedure TForm1.Button1Click(Sender: TObject);
begin
  SetColumnFullWidth(StringGrid1, 4);
end;

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