找到最接近鼠标位置的点 [英] find closest point to mouse position

问题描述

我有一个精灵的网格。
现在我想在一个网格元素上拖动图像。
因此，我需要知道网格元素的哪个x / y是最接近鼠标位置的点。
所有的网格元素都存储在一个数组中。
如何才能做到这一点？

解决方案

如果您只需要最接近的网格的x，y，那么所有你必须这样做。

  var gridX：int = Math.floor（mouseX / NumberOfColumns）; 
 var gridY：int = Math.floor（mouseY / NumberOfRows）; 
  

这会将您的鼠标坐标转换为网格坐标。

现在出现这个问题。如果将它们存储在一个2d数组中，那么如果将它们存储在一个平面数组（1d）中，则需要按照您创建它的方式查找它。

  var myObject：Object = my2dArray [gridX，gridY]; 
 var myObject：Object = myFlatArray [（gridX * NumberOfRows）+ gridY]; 
  

如果您已经考虑过如何创建数组并将它们推入其中，那应该是没有问题检索的东西没有搜索它。

I've got a grid of sprites. Now I would like to drag an image on a grid-element. Therefore I need to know which x/y of the grid-element is the closest point to the mouse-position. All the grid-elements are stored in an array. How can I achieve that?

解决方案

If all you need is the x,y of the closest grid then all you have to do is.

var gridX:int = Math.floor(mouseX / NumberOfColumns);
var gridY:int = Math.floor(mouseY / NumberOfRows);

This will convert your mouse coordinates to your grid coordinates.

Now comes the problem. If your storing them in a 2d array then you have your x/y if your storing them in a flat array (1d) you need to look it up just like you created it.

var myObject:Object = my2dArray[gridX, gridY];
var myObject:Object = myFlatArray[(gridX * NumberOfRows) + gridY];

If you have taken care of how you create your array and push the items in it, it should be no problem to retrieve stuff without searching it.

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