将文件转换为MultiPartFile [英] Converting File to MultiPartFile

问题描述

有什么办法将File对象转换为MultiPartFile？因此，我可以将该对象发送给接受 MultiPartFile 接口的对象的方法

  File myFile = new File（/ path / to / the / file.txt）
 
 MultiPartFile ....？ 
 
 def（MultiPartFile文件）{
 def is = new BufferedInputStream（file.getInputStream（））
 //对流
做一些有趣的事情
  

解决方案

MockMultipartFile 为此存在。正如在你的片段中，如果文件路径是已知的，下面的代码适用于我。

  import java.nio.file.Files ; 
 import java.nio.file.Path; 
 import java.nio.file.Paths; 
 import org.springframework.mock.web.MockMultipartFile; 
 
 Path path = Paths.get（/ path / to / the / file.txt）; 
 String name =file.txt; 
字符串originalFileName =file.txt; 
 String contentType =text / plain; 
 byte [] content = null; 
尝试{
 content = Files.readAllBytes（path）; 
} catch（final IOException e）{
} 
 MultipartFile result = new MockMultipartFile（name，
 originalFileName，contentType，content）; 
  

Is there any way to convert a File object to MultiPartFile? So that I can send that object to methods that accept the objects of MultiPartFile interface?

File myFile = new File("/path/to/the/file.txt")

MultiPartFile ....?

def (MultiPartFile file) {
  def is = new BufferedInputStream(file.getInputStream())
  //do something interesting with the stream
}

解决方案

MockMultipartFile exists for this purpose. As in your snippet if the file path is known, the below code works for me.

import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import org.springframework.mock.web.MockMultipartFile;

Path path = Paths.get("/path/to/the/file.txt");
String name = "file.txt";
String originalFileName = "file.txt";
String contentType = "text/plain";
byte[] content = null;
try {
    content = Files.readAllBytes(path);
} catch (final IOException e) {
}
MultipartFile result = new MockMultipartFile(name,
                     originalFileName, contentType, content);

这篇关于将文件转换为MultiPartFile的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！