如何在Groovy中将列表拆分为相同大小的列表？ [英] How to split a list into equal sized lists in Groovy?

问题描述

  def array = [1,2,3,4,5,6] 
  

是否有内置的允许我这样做（或类似的）：

  array.split（2）
  

并获得：

  [[1,2]，[3,4]，[5,6]] 
  

？

解决方案我同意Chris的观点，即groovy没有任何内容可以处理这个问题（至少对于2个以上的分区），但是我将你的问题解释为提出与他不同的问题。这里有一个实现我认为你所要求的：

  def分区（数组，大小）{
 def partitions = [] 
 int partitionCount = array.size（）/ size 
 
 partitionCount.times {partitionNumber  - > 
 def start = partitionNumber * size 
 def end = start + size  -  1 
分区<<数组[开始..结束] 
} 
 
 if（array.size（）％size）分区<< array [partitionCount * size ..- 1] 
返回分区
} 
 
 
 def origList = [1，2，3，4，5，6] 
 assert [[1]，[2]，[3]，[4]，[5]，[6]]分区（origList，1）
 assert [[1,2] 3，4]，[5,6]] == partition（origList，2）
 assert [[1,2,3]，[4,5,6]] == partition（origList，3）
 assert [[1,2,3,4]，[5,6]]分区（origList，4）
 assert [[1,2,3,4,5]，[6] ] ==分区（origList，5）
 assert [[1,2,3,4,5,6]] ==分区（origList，6）
  pre> 
If I have this:
def array = [1,2,3,4,5,6]
Is there some built-in which allows me to do this ( or something similar ):
array.split(2)
and get:
[[1,2],[3,4],[5,6]]
?
解决方案
I agree with Chris that there isn't anything built into groovy to handle this (at least for more than 2 partitions), but I interpreted your question to be asking something different than he did.  Here's an implementation that does what I think you're asking for:
def partition(array, size) {
    def partitions = []
    int partitionCount = array.size() / size

    partitionCount.times { partitionNumber ->
        def start = partitionNumber * size 
        def end = start + size - 1
        partitions << array[start..end]    
    }

    if (array.size() % size) partitions << array[partitionCount * size..-1]
    return partitions    
}


def origList = [1, 2, 3, 4, 5, 6]
assert [[1], [2], [3], [4], [5], [6]] == partition(origList, 1)
assert [[1, 2], [3, 4], [5, 6]] == partition(origList, 2)
assert [[1, 2, 3], [4, 5, 6]] == partition(origList, 3)
assert [[1, 2, 3, 4], [5, 6]] == partition(origList, 4)
assert [[1, 2, 3, 4, 5], [6]] == partition(origList, 5)
assert [[1, 2, 3, 4, 5, 6]] == partition(origList, 6)


                        
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