使用Groovy（gpath）获取XML属性的值 [英] Get value of an XML attribute with Groovy (gpath)

问题描述

在groovy中使用XmlParser（）。
请参阅以下代码。当 name 的值是 type 时，我需要打印 answer 的值。

 < root> 
< foo name ='type'answer ='car'/> 
< foo name ='color'answer ='red'/> 
< foo name ='size'answer ='big'/> 
< / root> 
  

我需要这样做：

  def XML = new XmlParser（）。parseText（XMLstring）
 println XML.root.foo。[where @name ='type']。@ answer 
  

解决方案

我无法分辨您是否期望存在多个匹配或if你知道会有一个。以下将找到他们并打印他们的答案。

  source ='''
< root> 
< foo name ='type'answer ='car'/> 
< foo name ='color'answer ='red'/> 
< foo name ='size'answer ='big'/> 
< / root> 
'''
 xml = new XmlParser（）。parseText（source）
 
 results = xml.findAll {it。@ name =='type'} 
 
 results.each {
 println it。@ answer 
} 
  

我希望有帮助。

编辑： 如果您知道存在只有一个你可以这样做...

。@ answer

另一个选项（您有几个）：

  xml = new XmlParser（）。parseText（source）
 
 xml.each {
 if（it。@ name == 'type'）{
 println it。@ answer 
} 
} 
  

Using XmlParser() in groovy. See the following code. I need to print the value of answer when the value of name is type.

   <root>
        <foo name = 'type' answer  = 'car'/>
        <foo name = 'color' answer = 'red'/>
        <foo name = 'size' answer = 'big'/>
    </root>

I need to do something like this:

def XML = new XmlParser().parseText(XMLstring)
println XML.root.foo.[where  @name = 'type'].@answer

解决方案

I can't tell if you expect there to be multiple matches or if you know there will be exactly one. The following will find them all and print their answer.

source = '''
<root>
    <foo name = 'type' answer  = 'car'/>
    <foo name = 'color' answer = 'red'/>
    <foo name = 'size' answer = 'big'/>
</root>
'''
xml = new XmlParser().parseText(source)

results = xml.findAll { it.@name == 'type' }

results.each {
    println it.@answer
}

I hope that helps.

EDIT:

If you know there is only one you can do something like this...

println xml.find { it.@name == 'type' }.@answer

Yet another option (you have several):

xml = new XmlParser().parseText(source)

xml.each { 
    if(it.@name == 'type') {
        println it.@answer
    }
}

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