Groovy等价于Scala隐式参数 [英] Groovy equivalent for Scala implicit parameters

问题描述

是否有一些Groovy替代方法可以表达如下内容：

  def doSomethingWith（implicit i：Int）= println（ got+ i）
 implicit var x = 5 
 
 doSomethingWith（6）//得到6 
 doSomethingWith //得到5 
 
x = 0 
 doSomethingWith //得到0 
  

更新：在这里查看后续问题：格罗维等价的Scala隐式参数 - 扩展

  doSomethingWith = <解析方案>  value = 5 
 
 doSomethingWith（6）//得到6 
 doSomethingWith（）//得到5 
 
值= 0 
 doSomethingWith（）//得到0 
  

Is there some Groovy alternative to express something like the following:

def doSomethingWith(implicit i:Int) = println ("Got "+i)
implicit var x = 5

doSomethingWith(6)  // Got 6
doSomethingWith     // Got 5

x = 0
doSomethingWith     // Got 0

Update: see a followup question here: Groovy equivalent for Scala implicit parameters - extended

解决方案

You can use closures with a default parameter:

doSomethingWith = { i = value -> println "Got $i" }
value = 5

doSomethingWith(6)  // Got 6
doSomethingWith()   // Got 5

value = 0
doSomethingWith()   // Got 0

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