验证在Android的一个手机号码 [英] Validation for a cell number in Android

问题描述

予有其中用户进入细胞数量的UI和号码存储在一个字符串变量然后将其存储到数据库中。

我想验证字符串检查字符串是否不包含任何字符。

我该怎么办呢？

下面是字符串code。

 的EditText editText3 =（EditText上）this.findViewById（R.id.editText2）;
。setNum = editText3.getText（）的toString（）; // setNum将包含一些链接8081124589
 

解决方案

要验证一个字符串，用

 如果（setNum.matches（regexStr））
 

在这里regexStr可以是：

仅

  //比赛号码
字符串regexStr =^ [0-9] * $

//只匹配10位数字
字符串regexStr =^ [0-9] {10} $

//匹配数字和破折号，任何顺序真的。
字符串regexStr =^ [0-9 \\  - ] * $

//匹配9999999999，1-999-999-9999和999-999-9999
字符串regexStr =^（1 \\  - ）？[0-9] {3} \\  - ？[0-9] {3} \\  - ？[0-9] {4} $
 

---

有一个很长的正则表达式来验证电话在美国（7至10位，扩展允许的，等等）。来源是这样的回答：<一href="http://stackoverflow.com/questions/123559/a-com$p$phensive-regex-for-phone-number-validation/123666#123666">A COM prehensive的正则表达式的电话号码验证

 字符串regexStr = "^(?:(?:\\+?1\\s*(?:[.-]\\s*)?)?(?:\\(\\s*([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\\s*\\)|([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))\\s*(?:[.-]\\s*)?)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\\s*(?:[.-]\\s*)?([0-9]{4})(?:\\s*(?:#|x\\.?|ext\\.?|extension)\\s*(\\d+))?$"
 

I have a UI where user enters the cell number and the number is stored in a string variable and then its stored into the database.

I want to validate the string to check whether the string does not contain any characters.

How do I do that?

Below is the string code.

EditText editText3 = (EditText) this.findViewById(R.id.editText2);
setNum = editText3.getText().toString(); //setNum would contain something link 8081124589

解决方案

To validate a string, use

if (setNum.matches(regexStr))

where regexStr can be:

//matches numbers only
String regexStr = "^[0-9]*$"

//matches 10-digit numbers only
String regexStr = "^[0-9]{10}$"

//matches numbers and dashes, any order really.
String regexStr = "^[0-9\\-]*$"

//matches 9999999999, 1-999-999-9999 and 999-999-9999
String regexStr = "^(1\\-)?[0-9]{3}\\-?[0-9]{3}\\-?[0-9]{4}$"

---

There's a very long regex to validate phones in the US (7 to 10 digits, extensions allowed, etc.). The source is from this answer: A comprehensive regex for phone number validation

String regexStr = "^(?:(?:\\+?1\\s*(?:[.-]\\s*)?)?(?:\\(\\s*([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\\s*\\)|([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))\\s*(?:[.-]\\s*)?)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\\s*(?:[.-]\\s*)?([0-9]{4})(?:\\s*(?:#|x\\.?|ext\\.?|extension)\\s*(\\d+))?$"

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