Groovy和XML：无法插入处理指令 [英] Groovy and XML: Not able to insert processing instruction

问题描述

需要更新现有XML文件中的某些属性。该文件包含XSL处理指令，因此，在解析和更新XML时，我需要在将指令再次写入文件之前添加该指令。问题是 - 无论我做什么 - 我无法插入处理指令

Need to update some attributes in an existing XML-file. The file contains a XSL processing instruction, so when the XML is parsed and updated I need to add the instruction before writing it to a file again. Problem is - whatever I do - I'm not able to insert the processing instruction

根据在rgagnon.com上找到的Java示例我已经创建了下面的代码

Based on the Java-example found at rgagnon.com I have created the code below

import groovy.xml.*

def xml = '''|<something>
            |  <Settings>
            |  </Settings>
            |</something>'''.stripMargin()

def document = DOMBuilder.parse( new StringReader( xml ) )
def pi = document.createProcessingInstruction('xml-stylesheet', 'type="text/xsl"    href="Bp8DefaultView.xsl"');
document.insertBefore(pi, document.documentElement) 

println document.documentElement

创建输出

<?xml version="1.0" encoding="UTF-8"?>
<something>
  <Settings>
  </Settings>
</something>

我要的是什么

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="Bp8DefaultView.xsl"?>
<something>
  <Settings>
  </Settings>
</something>

推荐答案

$ c> documentElement ，但是只传递元素到 println 。如果您打印整个文档？

You're inserting the PI before the documentElement, but then passing only the element to println. Does it work if you print the whole document?

，它会起作用如果不这样做，输出DOM的官方方法document是使用 LSSerializer

Failing that, the "official" way to output a DOM document is to use LSSerializer

def ser = document.implementation.createLSSerializer()
new File("output.xml").withOutputStream { o ->
  def lso = document.implementation.createLSOutput()
  lso.byteStream = o
  ser.write(document, lso)
}

这篇关于Groovy和XML：无法插入处理指令的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！