groovy用空间替换文件中的数据 [英] groovy replace data from file with space

问题描述

我想从文件中替换字符串。
i有这样一行：

i want to replace string from a file. i have a line like this:

qwe{data:"dede-dddd-ssss",login:"user",display:"screen"},abc,xyz

我想从数据中取代所有字符串使用空格登录

i want to replace all string starting from data to login with spaces

我试试这个我只能替换字符串，是否有一种方法可以替换字符串的起始和终止符？

i try this i can only replace the string, is there a way to replace with a starting and endpoint for string?

def source = new File("c:\\sq\\file1.txt") 
def dest = new File("c:\\sq\\file2.txt") 

def fileText = source.text
def filedest = dest.text
for ( index in 1..9 ) {
    fileText = (fileText =~ /data/).replaceFirst("")

推荐答案

此代码具有一个锚定版本（至 {）的正则表达式的：

This code has an anchored version (to {) of the regex:

def fileText = '''\
qwe{data:"dede-dddd-ssss",login:"user",display:"screen1"},abc,xyz
...
qwe{data:"data2",login:"user2",display:"screen2"},abc,xyz
...
qwe{data:"data3",login:"user3",display:"screen3"},abc,xyz\
'''

fileText = fileText.replaceAll(/(?<=\{)\s*data:[^,]+,\s*login:[^,]+,/ , '')
println fileText

输出：

Output:

qwe{display:"screen1"},abc,xyz
...
qwe{display:"screen2"},abc,xyz
...
qwe{display:"screen3"},abc,xyz

试试在线常规Web控制台

更新

如果您正确理解您的请求：以下代码读取 source （ c：\\sq\\file1.txt ）并将修改后的文本放入目标文件 dest （ c：\\sq\\file2.txt ）：

If a understand correctly your request: this following code read the input text from source (c:\\sq\\file1.txt) and put the modified text into destination file dest (c:\\sq\\file2.txt):

def source = new File("c:\\sq\\file1.txt") 
def dest = new File("c:\\sq\\file2.txt") 

dest.write(source.text
  .replaceAll(/(?<=\{)\s*data:[^,]+,\s*login:[^,]+,/ , '') )

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