我如何在MySQL中做一个连续的组? [英] How can I do a contiguous group by in MySQL?

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问题描述

如何在MySQL中返回实际上是连续GROUP BY的内容。换句话说,一个尊重记录集顺序的GROUP BY?



例如, SELECT MIN(col1),col2,COUNT(*) FROM table下面的表GROUP1 col2 ORDER BY col1 ,其中col1是一个唯一的有序索引:

 
1 a
2 a
3 b
4 b
5 a
6 a

收益:

 1 a 4 
3 b 2

但我需要返回以下内容:

 1 a 2 
3 b 2
5 a 2


解决方案

使用:

  SELECT MIN(t.id )'mi',
t.val,
COUNT(*)
FROM(SELECT x.id,
x.val,
CASE
WHEN xt.val IS NULL OR xt.val!= x.val THEN
@rownum:= @ rownum + 1
ELSE
@rownum
END AS grp
FROM TABLE x
JOIN(SELECT @rownum:= 0)r
LEFT JOIN(SELECT t.id +1'id',
t.val
FROM TABLE t)xt ON xt.id = x.id)t
GROUP BY t.val,t.grp
ORDER BY mi

这里的关键是创建一个可以进行分组的人为值。



以前,修正的Guffa答案:

pre $ SELECT t.id,t.val
FROM TABLE t
LEFT JOIN TABLE t2 on t2.id + 1 = t.id
WHERE t2.val IS NULL
OR t.val<> t2.val


How can I return what would effectively be a "contiguous" GROUP BY in MySQL. In other words a GROUP BY that respects the order of the recordset?

For example, SELECT MIN(col1), col2, COUNT(*) FROM table GROUP BY col2 ORDER BY col1 from the following table where col1 is a unique ordered index:

1    a
2    a
3    b
4    b
5    a
6    a

returns:

1    a    4
3    b    2

but I need to return the following:

1    a    2
3    b    2
5    a    2

解决方案

Use:

   SELECT MIN(t.id) 'mi', 
          t.val, 
          COUNT(*)
     FROM (SELECT x.id, 
                 x.val, 
                 CASE 
                   WHEN xt.val IS NULL OR xt.val != x.val THEN 
                     @rownum := @rownum+1 
                   ELSE 
                     @rownum 
                 END AS grp
            FROM TABLE x
            JOIN (SELECT @rownum := 0) r
       LEFT JOIN (SELECT t.id +1 'id',
                         t.val
                    FROM TABLE t) xt ON xt.id = x.id) t
 GROUP BY t.val, t.grp
 ORDER BY mi

The key here was to create an artificial value that would allow for grouping.

Previously, corrected Guffa's answer:

   SELECT t.id, t.val
     FROM TABLE t
LEFT JOIN TABLE t2 on t2.id + 1 = t.id
    WHERE t2.val IS NULL 
       OR t.val <> t2.val

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