我如何在MySQL中做一个连续的组? [英] How can I do a contiguous group by in MySQL?
问题描述
如何在MySQL中返回实际上是连续GROUP BY的内容。换句话说,一个尊重记录集顺序的GROUP BY?
例如, SELECT MIN(col1),col2,COUNT(*) FROM table下面的表GROUP1 col2 ORDER BY col1
,其中col1是一个唯一的有序索引:
1 a
2 a
3 b
4 b
5 a
6 a
收益:
1 a 4
3 b 2
但我需要返回以下内容:
1 a 2
3 b 2
5 a 2
使用:
SELECT MIN(t.id )'mi',
t.val,
COUNT(*)
FROM(SELECT x.id,
x.val,
CASE
WHEN xt.val IS NULL OR xt.val!= x.val THEN
@rownum:= @ rownum + 1
ELSE
@rownum
END AS grp
FROM TABLE x
JOIN(SELECT @rownum:= 0)r
LEFT JOIN(SELECT t.id +1'id',
t.val
FROM TABLE t)xt ON xt.id = x.id)t
GROUP BY t.val,t.grp
ORDER BY mi
这里的关键是创建一个可以进行分组的人为值。
以前,修正的Guffa答案:
pre $ SELECT t.id,t.val
FROM TABLE t
LEFT JOIN TABLE t2 on t2.id + 1 = t.id
WHERE t2.val IS NULL
OR t.val<> t2.val
How can I return what would effectively be a "contiguous" GROUP BY in MySQL. In other words a GROUP BY that respects the order of the recordset?
For example, SELECT MIN(col1), col2, COUNT(*) FROM table GROUP BY col2 ORDER BY col1
from the following table where col1 is a unique ordered index:
1 a 2 a 3 b 4 b 5 a 6 a
returns:
1 a 4 3 b 2
but I need to return the following:
1 a 2 3 b 2 5 a 2
Use:
SELECT MIN(t.id) 'mi',
t.val,
COUNT(*)
FROM (SELECT x.id,
x.val,
CASE
WHEN xt.val IS NULL OR xt.val != x.val THEN
@rownum := @rownum+1
ELSE
@rownum
END AS grp
FROM TABLE x
JOIN (SELECT @rownum := 0) r
LEFT JOIN (SELECT t.id +1 'id',
t.val
FROM TABLE t) xt ON xt.id = x.id) t
GROUP BY t.val, t.grp
ORDER BY mi
The key here was to create an artificial value that would allow for grouping.
Previously, corrected Guffa's answer:
SELECT t.id, t.val
FROM TABLE t
LEFT JOIN TABLE t2 on t2.id + 1 = t.id
WHERE t2.val IS NULL
OR t.val <> t2.val
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