从具有每个不同candidate_id的最近日期的行中返回数据 [英] Return the data from the rows with the most recent date of each distinct candidate_id
问题描述
我试图从每个不同的candidate_id的最近日期的行中返回数据。它正确地返回最近的日期(created_unix列),而不是相应行中的其余数据。
SELECT candidate_id,message,max(created_unix),jobpost_id,staffuserid
FROM messages
WHERE employer_id ='$ employerid'AND last ='company'
GROUP BY candidate_id
解决方案您必须
group by
everything不使用聚合函数:
$ p $SELECT candidate_id,message,max(created_unix),jobpost_id,staffuserid
FROM messages
WHERE employer_id ='$ employerid'AND last ='company'
GROUP BY candidate_id,message,jobpost_id,staffuserid
如果您的消息
每行不同,并且您希望通过candidate_id 组<,那么你不能使用
消息
。在这种情况下,只需将它从您的选择列表中删除,并且您不需要它在组中按
列表排序。请注意,使用聚合函数时,必须包含聚合函数或按
分组。否则,SQL将不知道从哪一行获取返回的行的数据。
更新:
在看到您要找的内容后,这可以实现:
SELECT candidate_id, message,max(created_unix),jobpost_id,staffuserid
FROM messages
WHERE employer_id ='$ employerid'AND last ='company'AND
created_unix =(
SELECT max(subm。 created_unix)
FROM messages subm
WHERE subm.candidate_id = messages.candidate_id
)
I am attempting to return the data from the rows with the most recent date of each distinct candidate_id. It is correctly returning the most recent date (the created_unix column), but not the rest of the data from the corresponding row.
SELECT candidate_id, message, max(created_unix), jobpost_id, staffuserid
FROM messages
WHERE employer_id='$employerid' AND last='company'
GROUP BY candidate_id
You must group by
everything not using an aggregate function:
SELECT candidate_id, message, max(created_unix), jobpost_id, staffuserid
FROM messages
WHERE employer_id='$employerid' AND last='company'
GROUP BY candidate_id, message, jobpost_id, staffuserid
If your message
is different per row and you want to group by candidate_id
, then you must not be using message
. In that case, simply remove it from your select list and you won't need it in your group by
list. The same goes for any other field you aren't using.
Remember, when using aggregate functions, you must contain each field in either an aggregate function or the group by
. Otherwise, SQL won't know from which row to pull the data for the row returned.
Update:
After seeing what you're looking for, this will do the trick:
SELECT candidate_id, message, max(created_unix), jobpost_id, staffuserid
FROM messages
WHERE employer_id='$employerid' AND last='company' AND
created_unix = (
SELECT max(subm.created_unix)
FROM messages subm
WHERE subm.candidate_id = messages.candidate_id
)
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