Python Pandas:我怎样才能将一个id分配给一个组中的所有项目? [英] Python Pandas: How can I group by and assign an id to all the items in a group?

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问题描述

我有df:

 域名orgid 
csyunshu.com 108299
dshu.com 108299
bbbdshu.com 108299
cwakwakmrg.com 121303
ckonkatsunet.com 121303

我想添加一个新列,用每个orgid的数字id替换域列:

 域orgid domainid 
csyunshu.com 108299 1
dshu.com 108299 2
bbbdshu.com 108299 3
cwakwakmrg.com 121303 1
ckonkatsunet.com 121303 2

我已经尝试过这一行,但它并没有给出我想要的结果:



$ b

  df.groupby('orgid')。count ['domain']。reset_index()

任何人都可以帮忙吗?

解决方案

您可以调用 code> groupby 对象并传入param method ='first'

 <$ c $在[61]中:
df ['domainId'] = df.groupby('orgid')['orgid']。rank(method ='first')
df

出[61]:
域名orgid domainId
0 csyunshu.com 108299 1
1 dshu.com 108299 2
2 bbbdshu.com 108299 3
3 cwakwakmrg.com 121303 1
4 ckonkatsunet.com 121303 2

如果您想覆盖你可以这样做:

  df ['domain'] = df.groupby('orgid')['orgid']。 rank(method ='first')


I have df:

domain           orgid
csyunshu.com    108299
dshu.com        108299
bbbdshu.com     108299
cwakwakmrg.com  121303
ckonkatsunet.com    121303

I would like to add a new column with replaces domain column with numeric ids per orgid:

domain           orgid   domainid
csyunshu.com    108299      1
dshu.com        108299      2
bbbdshu.com     108299      3
cwakwakmrg.com  121303      1
ckonkatsunet.com 121303     2

I have already tried this line but it does not give the result I want:

df.groupby('orgid').count['domain'].reset_index()

Can anybody help?

解决方案

You can call rank on the groupby object and pass param method='first':

In [61]:
df['domainId'] = df.groupby('orgid')['orgid'].rank(method='first')
df

Out[61]:
             domain   orgid  domainId
0      csyunshu.com  108299         1
1          dshu.com  108299         2
2       bbbdshu.com  108299         3
3    cwakwakmrg.com  121303         1
4  ckonkatsunet.com  121303         2

If you want to overwrite the column you can do:

df['domain'] = df.groupby('orgid')['orgid'].rank(method='first')

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