Grunt扩展文件,src中可以接受哪些模式? [英] Grunt expand files, what patterns are acceptable in src?

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问题描述

来自gruntfile.js的代码片段

  sass:{
compile:{
files:[{
展开:true,
cwd:'css /',
src:['^ [^ _]。scss'],
dest:'../css/' ,
ext:'.css'
}]
}
},

根据rubular,这应该工作在



基本上我想编译'css'目录中的所有.scss文件,除非它们以下划线开头。然而,这种模式不匹配任何东西?



任何想法?

解决方案

试试这个模式: ['*。scss','!_ *。scss'] 。这将使得区别更加明确。

  sass:{
compile:{
files :[{
expand:true,
cwd:'css /',
src:['* .scss','!_ *。scss'],
dest: '../css/',
ext:'.css'
}]
}
},
$ b $ p

如果要递归匹配( cwd 子文件夹中的文件),请使用 ** / *

  sass:{
compile:{
files:[ {
expand:true,
cwd:'css /',
src:['** / *。scss','!** / _ *。scss'],
dest:'../css/',
ext:'.css'
}]
}
},

详细了解 Grunt Globbing Patterns 与正式表达式不一样sions


Snippet from gruntfile.js

sass: {
    compile: {
        files: [{
            expand: true,
            cwd: 'css/',
            src: ['^[^_].scss'],
            dest: '../css/',
            ext: '.css'
        }]
    }
},

This should work according to rubular.

Basically I want to compile all .scss files in the 'css' directory, unless they start with an underscore. However, that pattern doesn't match anything?

Any ideas?

解决方案

Try this pattern: ['*.scss', '!_*.scss']. It'll make the distinction more explicit, too.

sass: {
    compile: {
        files: [{
            expand: true,
            cwd: 'css/',
            src: ['*.scss', '!_*.scss'],
            dest: '../css/',
            ext: '.css'
        }]
    }
},

If you want to match recursively (files in subfolders of cwd), use **/*

sass: {
    compile: {
        files: [{
            expand: true,
            cwd: 'css/',
            src: ['**/*.scss', '!**/_*.scss'],
            dest: '../css/',
            ext: '.css'
        }]
    }
},

Learn more about Grunt Globbing Patterns, which aren't the same as regular expressions.

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