在Android的触摸释放方法 [英] Touch Release method in Android

问题描述

我试图捕捉TouchRelease事件的Andr​​oid。我已经看到，event.getAction（）返回操作类型。但里面的的onTouchEvent它总是给行动ACTION_DOWN。你知道如何捕捉触摸RELASE事件。

 公共布尔的onTouchEvent（MotionEvent事件）{
        Log.d（TAG，+ event.getAction（））;
        返回super.onTouchEvent（事件）;
    }
 

解决方案

您 ACTION_UP ：<一href="http://developer.android.com/reference/android/view/MotionEvent.html#ACTION_UP">http://developer.android.com/reference/android/view/MotionEvent.html#ACTION_UP

 查看视图=新的View（）;

view.setOnTouchListener（新OnTouchListener（）{
  公共布尔onTouch（查看视图，MotionEvent事件）{
    如果（event.getAction（）== android.view.MotionEvent.ACTION_DOWN）{
      Log.d（TouchTest，降落）;
    }否则，如果（event.getAction（）== android.view.MotionEvent.ACTION_UP）{
      Log.d（TouchTest，润色）;
    }
  }
}
 

I'm trying to capture the TouchRelease event in Android. I have seen that event.getAction() returns the action type. But inside "onTouchEvent" it always gives the action "ACTION_DOWN". Do you know how to capture the touch relase event.

public boolean onTouchEvent(MotionEvent event) {
        Log.d(TAG,""+event.getAction());
        return super.onTouchEvent(event);
    }

解决方案

You have ACTION_UP: http://developer.android.com/reference/android/view/MotionEvent.html#ACTION_UP

View view = new View();

view.setOnTouchListener(new OnTouchListener () {
  public boolean onTouch(View view, MotionEvent event) {
    if (event.getAction() == android.view.MotionEvent.ACTION_DOWN) {
      Log.d("TouchTest", "Touch down");
    } else if (event.getAction() == android.view.MotionEvent.ACTION_UP) {
      Log.d("TouchTest", "Touch up");
    }
  }
}

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