我如何为Gson编写定制的JSON解串器? [英] How do I write a custom JSON deserializer for Gson?
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问题描述
我有一个Java类,用户:
public class User
{
int id;
字符串名称;
时间戳updateDate;
}
我收到一个包含来自webservice的用户对象的JSON列表:
[{id:1,name:Jonas,update_date:1300962900226},
{id:5,name:Test,date_date:1304782298024}]
@Override
public User反序列化(JsonElement json,Type类型,
JsonDeserializationContext上下文)throws JsonParseException {
返回新用户(
json.getAsJsonPrimitive()。getAsInt(),
json.getAsString(),
json.getAsInt(),
(Timestamp)context.deserialize(json.getAsJsonPrimitive(),
Timestamp.class));
}
但是我的反序列化器不起作用。我怎样才能为Gson编写一个自定义的JSON解串器?
解决方案
@Override
public public deserialize(JsonElement json,Type type,
JsonDeserializationContext context)throws JsonParseException {
JsonObject jobject = json.getAsJsonObject();
返回新用户(
jobject.get(id)。getAsInt(),
jobject.get(name)。getAsString(),
新的时间戳(jobject.get(update_date)。getAsLong()));
}
我假设User类具有适当的构造函数。
I have a Java class, User:
public class User
{
int id;
String name;
Timestamp updateDate;
}
And I receive a JSON list containing user objects from a webservice:
[{"id":1,"name":"Jonas","update_date":"1300962900226"},
{"id":5,"name":"Test","date_date":"1304782298024"}]
I have tried to write a custom deserializer:
@Override
public User deserialize(JsonElement json, Type type,
JsonDeserializationContext context) throws JsonParseException {
return new User(
json.getAsJsonPrimitive().getAsInt(),
json.getAsString(),
json.getAsInt(),
(Timestamp)context.deserialize(json.getAsJsonPrimitive(),
Timestamp.class));
}
But my deserializer doesn't work. How can I write a custom JSON deserializer for Gson?
解决方案
@Override
public User deserialize(JsonElement json, Type type,
JsonDeserializationContext context) throws JsonParseException {
JsonObject jobject = json.getAsJsonObject();
return new User(
jobject.get("id").getAsInt(),
jobject.get("name").getAsString(),
new Timestamp(jobject.get("update_date").getAsLong()));
}
I'm assuming User class has the appropriate constructor.
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