GSON整数到特定字段的布尔值 [英] GSON Integer to Boolean for Specific Fields

问题描述

我正在处理一个返回整数的API（1 = true，other = false）来表示布尔值。

我见过这个问题和答案，但我需要能够指定应该应用哪个字段，因为有时整数实际上是整数。

编辑：传入的JSON可能看起来像这样（也可以是String而不是int等）：

  {
regular_int：1234，
int_that_should_be_a_boolean：1 
} 
  

我需要一种方法来指定应将 int_that_should_be_a_boolean 解析为布尔值，并且应将 regular_int 解析为一个整数。

解决方案

我们将为Gson提供一个小钩子，一个用于布尔的自定义解串器，即一个实现 JsonDeserializer< Boolean> 接口：
$ b CustomBooleanTypeAdapter

  import java.lang.reflect.Type; 
 import com.google.gson。*; 
类BooleanTypeAdapter实现JsonDeserializer< Boolean> 
 {
 public Boolean deserialize（JsonElement json，Type typeOfT，
 JsonDeserializationContext context）throws JsonParseException 
 {
 int code = json.getAsInt（）; 
返回码== 0？ false：
 code == 1？ true：
 null; 
 
 
 $ / code> 

要使用它，我们需要稍微改变一下我们使用工厂对象GsonBuilder获取 Gson 映射器实例的方式，GsonBuilder是使用 GSON 的常用模式方法。



  GsonBuilder builder = new GsonBuilder（）; 
 builder.registerTypeAdapter（Boolean.class，new BooleanTypeAdapter（））; 
 Gson gson = builder.create（）; 
  

对于原始类型使用低于1



  GsonBuilder builder = new GsonBuilder（）; 
 builder.registerTypeAdapter（boolean.class，new BooleanTypeAdapter（））; 
 Gson gson = builder.create（）; 
  

享受 JSON 解析！

I'm dealing with an API that sends back integers (1=true, other=false) to represent booleans.

I've seen this question and answer, but I need to be able to specify which field this should apply to, since some times an integer is actually an integer.

EDIT: The incoming JSON could possibly look like this (could also be String instead of int, etc...):

{ 
    "regular_int": 1234, 
    "int_that_should_be_a_boolean": 1
}

I need a way to specify that int_that_should_be_a_boolean should be parsed as a boolean and regular_int should be parsed as an integer.

解决方案

We will provide Gson with a little hook, a custom deserializer for booleans, i.e. a class that implements the JsonDeserializer<Boolean> interface:

CustomBooleanTypeAdapter

import java.lang.reflect.Type;
import com.google.gson.*;
class BooleanTypeAdapter implements JsonDeserializer<Boolean>
{
      public Boolean deserialize(JsonElement json, Type typeOfT, 
             JsonDeserializationContext context) throws JsonParseException
      {
          int code = json.getAsInt();
          return code == 0 ? false :
                   code == 1 ? true :
                 null;
      }
}

To use it we’ll need to change a little the way we get the Gson mapper instance, using a factory object, the GsonBuilder, a common pattern way to use GSON is here.

GsonBuilder builder = new GsonBuilder();
builder.registerTypeAdapter(Boolean.class, new BooleanTypeAdapter());
Gson gson = builder.create();

For primitive Type use below one

 GsonBuilder builder = new GsonBuilder();
    builder.registerTypeAdapter(boolean.class, new BooleanTypeAdapter());
    Gson gson = builder.create();

Enjoy the JSON parsing!

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