阻止GSON序列化JSON字符串 [英] Prevent GSON from serializing JSON string
问题描述
我是gson的新手,并且有新的问题,我没有找到答案,所以请耐心等待。 StackOverflow和Google不是我的朋友:(
)我有一个java类User,它的一个属性externalProfile是一个包含已经序列化的JSON 。当gson序列化User对象时,它会将externalProfile视为原始对象,从而转义JSON并添加额外的斜线等。
我希望gson将字符串单独留下,只是使用它原样,因为它已经是有效的和可用的JSON。
为了区分JSON字符串,我创建了一个名为JSONString的简单类,并且我尝试使用reader / writers,registerTypeAdapter,但没有任何效果。 b $ b你可以帮我吗?
public class User {
private JSONString externalProfile;
public void setExternalProfile(JSONString externalProfile){this.externalProfile = externalProfile;}
}
public final class JSONString {
private String simpleString;
public JSONString (String simpleString){this.simpleStrin g = simpleString; }
}
public customJsonBuilder(Object object){
GsonBuilder builder = new GsonBuilder();
builder.registerTypeAdapter(GregorianCalendar.class,new JsonSerializer< GregorianCalendar>(){
public JsonElement serialize(GregorianCalendar src,Type type,JsonSerializationContext context){
if(src == null){
return null;
}
返回新的JsonPrimitive(新的SimpleDateFormat(yyyy-MM-dd HH:mm:ss).format(src.getTime()));
}
});
Gson gson = builder.create();
return gson.toJson(object);
}
例如,externalProfile将会保持(如字符串值): p>
{profile:{registrationNumber:11111}}
在将它作为JSONString存储在User对象中后,我们将用户对象转换为JSON:
User user = new User();
user.setExternalProfile(new JSONString(externalProfile)),
String json = customJsonBuilder(user);
json将包含以下内容:
{\profile \:{\registrationNumber \:11111}}
因此,externalProfile JSONString由gson作为String原始序列化,在双引号前添加额外的斜线。
我希望gson按原样离开这个JSONString,因为它已经是可用的JSON。
我正在寻找一个类型适配器/读写器来做到这一点,但我无法让它工作。
首先将externalProfile作为JsonObject存储:
new Gson()。fromJson(externalProfile,JsonObject.class));
让gson在输出User对象时再次序列化它。
将产生完全相同的JSON!
I'm new to gson, and have newby question which I have not found an answer to, so please bear with me. StackOverflow and google were not my friend :(
I have a java class "User", and one of its properties, "externalProfile" is a Java String containing already serialized JSON. When gson serializes the User object, it will treat externalProfile as primitive and thus escaping the JSON adding extra slashes etc. I want gson to leave the string alone, just using it "as is", because it is already valid and usable JSON.
To distinguish the JSON string, I created a simple class called JSONString, and I've tried using reader/writers, registerTypeAdapter, but nothing works. Can you help me out?
public class User {
private JSONString externalProfile;
public void setExternalProfile(JSONString externalProfile) { this.externalProfile = externalProfile; }
}
public final class JSONString {
private String simpleString;
public JSONString(String simpleString) { this.simpleString = simpleString; }
}
public customJsonBuilder(Object object) {
GsonBuilder builder = new GsonBuilder();
builder.registerTypeAdapter(GregorianCalendar.class, new JsonSerializer<GregorianCalendar>() {
public JsonElement serialize(GregorianCalendar src, Type type, JsonSerializationContext context) {
if (src == null) {
return null;
}
return new JsonPrimitive(new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(src.getTime()));
}
});
Gson gson = builder.create();
return gson.toJson(object);
}
As en example, the externalProfile will hold (as String value):
{"profile":{"registrationNumber": 11111}}
After I store it as JSONString in the User object, and we convert the user object to JSON:
User user = new User();
user.setExternalProfile(new JSONString(externalProfile)),
String json = customJsonBuilder(user);
json will hold something like:
{\"profile\":{\"registrationNumber\": 11111}}
So, the externalProfile JSONString is serialized by gson as String primitive, adding the extra slashes in front of the doublequotes. I want gson to leave this JSONString as is, because it already is usable JSON. I'm looking for a type adapter / reader-writer to do this, but I can't get it to work.
As stated by Alexis C:
store the externalProfile as a JsonObject first:
new Gson().fromJson(externalProfile, JsonObject.class));
And let gson serialize this again when outputting the User object. Will produce exactly the same JSON!
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