从Json数组中提取信息 [英] Pull information from Json array

问题描述

所有，

在请求获取用户列表后，我有以下JSON响应。我想用userName只拉一个用户的id。例如，如果我想用户名Test1的id，该怎么做？任何帮助将不胜感激。

  {
displayLength：4，
iTotal ：
users：[
 {
id：2，
userName：Test1，
Group ：{id：1 
 name：Test-Admin
} 
}，
 {
id：17，
userName ：Test2，
Group：{id：1 
 name：Test-Admin
} 
}，
 {
 ID：32，
userName：Test3，
Group：{id：1 
 name：Test-Admin
} 
 
id：35，
userName：Test4，
Group：{id：1 
 name： Test-Admin
} 
 } 
 
 
 
 $ / code> 

谢谢，

解决方案

看下面的代码是否有帮助。只需将用户名传递给 userName 变量，让代码为您找到 userId 。

  JSONObject json = new JSONObject（{\ n+\displayLength \：\4 \，
 +\iTotal \：\20 \，\\\
+\users\：[\\\
+ {\ n
 +\id \：\2 \，\\\
+\userName \：\Test1 \， \\\

 +\Group \：{id：1，\\\
+name：\Test-Admin \\\\

 + } \\\
+}，\\\
+{\\\
+\id \：\17 \，\\\

 +\ userName \：\Test2 \，\\\
+\Group \：{id：1，\\\

 +name：\ Admin \\\\
+} \\\
+}，\\\

 + {\ n+\id \：\32 \，\\\
+\userName \：\Test3 \，\\\

 +\Group \：{id：1，\\\
+name：\Test-Admin \\\\

 +} \ n +}，\\\
+{\\\
+\id \：\35 \，\\\

 +\userName \ ：\Test4 \，\\\
+\Group \：{id：1，\\\

 +name：\Test-Admin \\\ \\ n+} \\\
+} \\\

 +\\\
+] \\\
+}）; 
 
 JSONArray array = json.getJSONArray（users）; 
 
 String userName =Test1; 
 Integer userId = null; 
 
 for（int i = 0; i< array.length（）&& userId == null; i ++）{
 
 JSONObject jsonIn =（JSONObject）array获得（ⅰ）; 
 
 if（jsonIn.optString（userName）。equals（userName））{
 userId = jsonIn.optInt（id）; 
 
 
 
 System.out.println（User Name for User Name'+ userName +'is：+ userId）; 
  




All,

I have following JSON response after request get list of users. I want to pull just only one user's id using userName. For example if i want id of userName Test1, how to do that? Any help will be appreciated.

      {
         "displayLength": "4",
         "iTotal": "20",
         "users": [
         {
            "id": "2",
            "userName": "Test1",
            "Group": {   id:1
                         name:"Test-Admin"
                         }
        },
        {
            "id": "17",
            "userName": "Test2",
            "Group": {   id:1
                         name:"Test-Admin"
                         }
        },
        {
            "id": "32",
            "userName": "Test3",
            "Group": {   id:1
                         name:"Test-Admin"
                         }
        },
        {
            "id": "35",
            "userName": "Test4",
            "Group": {   id:1
                         name:"Test-Admin"
                         }
        }  

    ]
   }

Thanks,

解决方案

See if this below code helps. Just pass user name to userName variable and let the code find the userId for you.

JSONObject json = new JSONObject(" {\n" + "         \"displayLength\": \"4\",\n"
        + "         \"iTotal\": \"20\",\n" + "         \"users\": [\n" + "         {\n"
        + "            \"id\": \"2\",\n" + "            \"userName\": \"Test1\",\n"
        + "            \"Group\": {   id:1,\n" + "                         name:\"Test-Admin\"\n"
        + "                         }\n" + "        },\n" + "        {\n" + "            \"id\": \"17\",\n"
        + "            \"userName\": \"Test2\",\n" + "            \"Group\": {   id:1,\n"
        + "                         name:\"Test-Admin\"\n" + "                         }\n" + "        },\n"
        + "        {\n" + "            \"id\": \"32\",\n" + "            \"userName\": \"Test3\",\n"
        + "            \"Group\": {   id:1,\n" + "                         name:\"Test-Admin\"\n"
        + "                         }\n" + "        },\n" + "        {\n" + "            \"id\": \"35\",\n"
        + "            \"userName\": \"Test4\",\n" + "            \"Group\": {   id:1,\n"
        + "                         name:\"Test-Admin\"\n" + "                         }\n" + "        }  \n"
        + "\n" + "    ]\n" + "   }");

JSONArray array = json.getJSONArray("users");

String userName = "Test1";
Integer userId = null;

for (int i = 0; i < array.length() && userId == null; i++) {

    JSONObject jsonIn = (JSONObject) array.get(i);

    if (jsonIn.optString("userName").equals(userName)) {
        userId = jsonIn.optInt("id");
    }
}

System.out.println("User ID for User Name '" + userName + "' is : " + userId);

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