如何使用gson和volley解析嵌套的json？ [英] How to use gson and volley parse nested json?

问题描述

下面是我要使用的json数据：

  {
name：Ravi Tamada ，
email：[e-mail]，
电话：
 {
home：08947 000000，
mobile ：[phone]
} 
 
} 
  

---

$ b $
$ b

这是我的JsonObjectRequest： ，null，new Response.Listener< JSONObject>（）{

@Override
public void onResponse（JSONObject jsonObject）{

Gson gson = new Gson（） ;
People people;
people = gson.fromJson（jsonObject.toString（），People.class）;
tv_city.setText（+ people.email）;

}
}，new Response.ErrorListener（）{
@Override
public void onErrorResponse（VolleyError volleyError）{



}
}）;

可以使用tv_city.setText（+ people.email（））... p>

---

这是我的javabean类：

  public class People {
 
 public String name; 
 public String email; 
 
公共类电话{
 public String home; 
 public String mobile; 
 
} 
 
} 
  

---

现在我想获得家庭号码，怎么样？

更新你的bean类，如下所示： -

  public class People实现Serializable {
 private String name; 
私人字符串电子邮件; 
私人电话电话; 
 
公用电话getPhone（）{
返回电话; 
} 
 
 public void setPhone（Phone phone）{
 this.phone = phone; 
} 
 public String getName（）{
 return name; 
} 
 
 public void setName（String name）{
 this.name = name; 
} 
 
 public String getEmail（）{
 return email; 
} 
 
 public void setEmail（String email）{
 this.email = email; 
}} 
  

2-创建一个新的Bean类Phone.java： -

  public class Phone implements Serializable {
 private String home; 
 
 public String getMobile（）{
 return mobile; 
} 
 
 public void setMobile（String mobile）{
 this.mobile = mobile; 
} 
 
 public String getHome（）{
 return home; 
} 
 
 public void setHome（String home）{
 this.home = home; 
} 
 
 private String mobile;} 
  

3-现在更新您的代码，如下所示：
$ b $ pre $ JsonObjectRequest jsonObjectRequest = new JsonObjectRequest（Request.Method.GET，APITEST，null，new Response。 Listener< JSONObject>（）{

@Override
public void onResponse（JSONObject jsonObject）{

Gson gson = new Gson（）;
People people;
people = gson.fromJson（jsonObject.toString（），People.class）;
tv_city.setText（+ people.email）;
//获取Home&手机号码
String home = people.getPhone.getHome（）;
String mobile = people.getPhone.getMobile（）;


}，new Response。 ErrorListener（）{
@Override
public void onErrorResponse（VolleyError volleyError）{


$ b}
}）;


注意： - 我的上面的bean是按照您的问题预期的api响应。但是如果你有嵌套的对象，那么你必须在你的内部选择 List< Phone> 或 ArrayList< Phone> People bean，然后创建它的getter和setter。

希望这对你有帮助!!!

Here is the json data I want to use:

{
     "name" : "Ravi Tamada", 
     "email" : "[e-mail]",
     "phone" : 
      {
         "home" : "08947 000000",
         "mobile" : "9999999999"
      }

}

---

Here is my JsonObjectRequest:

JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, APITEST,null, new Response.Listener<JSONObject>() {

        @Override
        public void onResponse(JSONObject jsonObject) {

            Gson gson = new Gson();
            People people;
            people = gson.fromJson(jsonObject.toString(),People.class);
            tv_city.setText(""+people.email);

        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError volleyError) {



        }
    });

It's ok with tv_city.setText(""+people.email())...

---

Here is my javabean class:

public class People {

    public String name ;
    public String email;

    public class Phone{
        public String home;
        public String mobile;

    }

}

---

Now I want to get "home" number,how?

解决方案

1- You have to update your bean class as follows :-

public class People implements Serializable {
private String name ;
private String email;
private Phone phone;

 public Phone getPhone () {
    return phone;
}

public void setPhone (Phone phone) {
    this.phone = phone;
}
public String getName () {
    return name;
}

public void setName (String name) {
    this.name = name;
}

public String getEmail () {
    return email;
}

public void setEmail (String email) {
    this.email = email;
}}

2- Create a new bean class Phone.java :-

public class Phone implements Serializable{
private String home;

public String getMobile () {
    return mobile;
}

public void setMobile (String mobile) {
    this.mobile = mobile;
}

public String getHome () {
    return home;
}

public void setHome (String home) {
    this.home = home;
}

private String mobile;}

3- Now update your code as follows:-

JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, APITEST,null, new Response.Listener<JSONObject>() {

    @Override
    public void onResponse(JSONObject jsonObject) {

        Gson gson = new Gson();
        People people;
        people = gson.fromJson(jsonObject.toString(),People.class);
        tv_city.setText(""+people.email);
        //for getting Home & Mobile number
          String home=people.getPhone.getHome();
          String mobile=people.getPhone.getMobile();

    }
}, new Response.ErrorListener() {
    @Override
    public void onErrorResponse(VolleyError volleyError) {



    }
});

Note:- My above bean is as per expected api response in your question. But if you have nested objects then you have to choose either List<Phone> or ArrayList<Phone> inside in your People bean and then create its getters and setters.

Hope this will help you !!!

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