使用带有Gulp的requirejs优化器节点模块 [英] Using requirejs optimizer node module with Gulp
问题描述
有 gulp-requirejs 插件,但它的列入黑名单,并显示以下消息:使用 require.js 模块直接。
文档相当稀少,我如何最好的将它与Gulp构建任务结合使用?
在文档中有一个示例:
var requirejs = require('requirejs');
var config = {
baseUrl:'../appDir/scripts',
name:'main',
out:'../build/main -built.js'
};
requirejs.optimize(config,function(buildResponse){
// buildResponse只是模块的文本输出
//包含了加载构建文件的内容。
//使用config.out获取优化的文件内容
var contents = fs.readFileSync(config.out,'utf8');
},function(err){
//优化错误回调
});
但是这对我没有多大帮助...这是我最好的尝试:
var gulp = require('gulp'),
r = require('requirejs')。optimize;
var config2 = {
baseUrl:'src / js',
名称:'config',
out:'dist / js / main-built.js '
};
$ b gulp.task('scripts3',function(){
gulp.src(['src / js / ** / *。js'])
.pipe( r(config)
.pipe(gulp.dest(config.out))
});
但requirejs模块不使用流,所以它不起作用。
还有非常友好的 amd-optimize ,但它与r.js不同。
我刚刚用gulp-shell运行 r.js
build命令:
var gulp = require('gulp'),
shell = require('gulp-shell');
//运行r.js命令,如此简单的获取:)
gulp.task('scripts',shell.task([
'r.js -o build / r / build.js'
] ))
运行大概需要2秒钟,不会太长。
b$ b
r设置是在一个外部的 build.js
文件中定义的,Gulp kn什么都没有。
There's gulp-requirejs plugin, but it's blacklisted with the following message: "use the require.js module directly".
The docs are quite sparse, how would I best use it in conjunction with Gulp build task?
In the docs there's an example:
var requirejs = require('requirejs');
var config = {
baseUrl: '../appDir/scripts',
name: 'main',
out: '../build/main-built.js'
};
requirejs.optimize(config, function (buildResponse) {
//buildResponse is just a text output of the modules
//included. Load the built file for the contents.
//Use config.out to get the optimized file contents.
var contents = fs.readFileSync(config.out, 'utf8');
}, function(err) {
//optimization err callback
});
But that doesn't help me much... Here's my best try:
var gulp = require('gulp'),
r = require('requirejs').optimize;
var config2 = {
baseUrl: 'src/js',
name: 'config',
out: 'dist/js/main-built.js'
};
gulp.task('scripts3', function() {
gulp.src(['src/js/**/*.js'])
.pipe(r(config)
.pipe(gulp.dest(config.out))
});
But the requirejs module doesn't use streams, so it won't work.
There's also the very Gulp friendly amd-optimize but it's not the same as r.js, yet.
I just ended up running the r.js
build command with gulp-shell:
var gulp = require('gulp'),
shell = require('gulp-shell');
// Run the r.js command, so simple taks :)
gulp.task('scripts', shell.task([
'r.js -o build/r/build.js'
]))
It takes roughly 2 seconds to run, not too long at all.
The r settings are defined in an external build.js
file that Gulp knows nothing about.
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