用gulp-notify和gulp-plumber处理错误 [英] Error handling with gulp-notify and gulp-plumber

问题描述

我想在以下情况下显示通知：

1.发生错误

2.脚本成功执行时

I want to display a notification when:
1. An error occurs
2. When the script was successfully executed

所有通知实际上都在工作，但即使发生错误，也会始终显示成功通知。

All notifications are actually working but the success notification is always displayed, even when there is an error.

如何确保

这是我当前的任务：

This is my current task:

var gulp = require('gulp');
var sass = require('gulp-ruby-sass');
var rename = require('gulp-rename');
var notify = require('gulp-notify');
var plumber = require('gulp-plumber');
var minifycss = require('gulp-minify-css');
var autoprefixer = require('gulp-autoprefixer');

gulp.task('sass', function(){
   return gulp.src('assets/scss/global.scss')
       .pipe(plumber({errorHandler: notify.onError("Error: <%= error.message %>")}))
       .pipe(sass({ style: 'expanded' }))
       .pipe(autoprefixer())
       .pipe(gulp.dest('assets/css/'))
       .pipe(rename({suffix: '.min'}))
       .pipe(minifycss())
       .pipe(gulp.dest('assets/css/'))
       .pipe(notify({
           title: 'Gulp',
           subtitle: 'success',
           message: 'Sass task',
           sound: "Pop"
       }));
});

gulp.task('watch', function(){
   gulp.watch('assets/scss/**/*.scss', ['sass']);
});

gulp.task('default', ['sass', 'watch']);

推荐答案

我遇到同样的问题， gulp-if和一个自定义错误处理程序。基本上，我在错误出现的时候设置了 errorFree = false ，然后在显示成功消息的时候使用 gulp-if 来确定是否调用 notify（）。

I encountered the same issue and what worked for me was gulp-if and a custom error handler. Basically, I set errorFree = false when an error is thrown then at the end when it's time to show the success message I use gulp-if to determine if notify() gets called or not.

使用您的gulp文件：

Working with your gulpfile:

var gulp = require('gulp');
var sass = require('gulp-ruby-sass');
var rename = require('gulp-rename');
var notify = require('gulp-notify');
var plumber = require('gulp-plumber');
var minifycss = require('gulp-minify-css');
var autoprefixer = require('gulp-autoprefixer');

gulp.task('sass', function(){

    var onError = function(err) {
        notify.onError({
                    title:    "Gulp",
                    subtitle: "Failure!",
                    message:  "Error: <%= error.message %>",
                    sound:    "Beep"
                })(err);

        this.emit('end');
    };

   return gulp.src('assets/scss/global.scss')
       .pipe(plumber({errorHandler: onError}))
       .pipe(sass({ style: 'expanded' }))
       .pipe(autoprefixer())
       .pipe(gulp.dest('assets/css/'))
       .pipe(rename({suffix: '.min'}))
       .pipe(minifycss())
       .pipe(gulp.dest('assets/css/'))
       .pipe(notify({ // Add gulpif here
           title: 'Gulp',
           subtitle: 'success',
           message: 'Sass task',
           sound: "Pop"
       }));
});

gulp.task('watch', function(){
   gulp.watch('assets/scss/**/*.scss', ['sass']);
});

gulp.task('default', ['sass', 'watch']);

在我的gulp文件中，我实际上将每一步包含在 gulp-if ，以便流停止处理。 （我没有找到一种方法来停止流而不杀死进程，这违背了IMO的目的。）

In my gulpfile I actually wrap each step in gulp-if so that the stream stops processing. (I haven't found a way to stop the stream without killing the process, which defeats the purpose of watch IMO.)

这篇关于用gulp-notify和gulp-plumber处理错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！