有接口扩展字符串功能 [英] Have interface extend string functionality

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问题描述

我一起使用这些工具:


  • TypeScript

  • Gulp

  • Gulp-Inject



我试图执行以下操作:

  module My {
interface IGulpInjectable extends string {//<<问题在这里!
[gulp_inject:string]:string;
}

export class Cache {
private items:{[key:string]:IGulpInjectable};
$ b构造函数(){
this.items = {
item1:{gulp_inject:file1.html},
item2:{gulp_inject: file2.html}
}
}

getItem(key:string){
return this.items [key] .trim();



gulp-inject 是用包含文件内容的字符串替换 {gulp_inject:x.html} 。这就是为什么我想要 IGulpInjectable 扩展字符串:这样像 trim() 将被TypeScript理解。



但是,扩展字符串无效。 都不扩展字符串。至少,不是用我目前的构造函数代码,我不希望改变它。



如何告诉TypeScript我的界面的所有方法都是字符串有?






脚注,我当前的解决方法:

  getItem(key:string){
return(< any> this.items [key])。trim();
}

但这并不令人满意。

  interface IGulpInjectable 

扩展字符串
{
gulp_inject:string;
}

class Cache
{
private items:{[key:string]:IGulpInjectable};


构造函数()
{

let item1 = new String(123);
item1 [gulp_inject] =file1.html;

let item2 = new String(4556);
item2 [gulp_inject] =file2.html;
$ b $ this.items = {
item1:< IGulpInjectable> item1,
item2:< IGulpInjectable> item2
}
}

getItem(key:string)
{
return this.items [key];
}
}

让c = new Cache();
let i = c.getItem(item1);
console.log(i.trim()); //输出'123'
console.log(i.gulp_inject); //输出'file1.html'

链接:打字游戏场



希望这会有所帮助。


I'm using these tools together:

  • TypeScript
  • Gulp
  • Gulp-Inject

I'm trying to do the following:

module My {
    interface IGulpInjectable extends string { // << Problem here!
        [gulp_inject: string] : string;
    }

    export class Cache {
        private items: { [key: string] : IGulpInjectable };

        constructor() {
            this.items = {
                "item1": { gulp_inject: "file1.html" },
                "item2": { gulp_inject: "file2.html" }
            }
        }

        getItem(key: string){
            return this.items[key].trim();
        }
    }
}

What gulp-inject does is replace { gulp_inject: "x.html" } with a string containing the file contents. This is why I want to have IGulpInjectable extend string: so that methods like trim() will be understood by TypeScript.

However, extends string is not valid. Neither is extends String. At least, not with my current constructor code, which I prefer not to change.

How can I tell TypeScript that my interface has all methods a string has?


Footnote, my current workaround:

        getItem(key: string){
            return (<any> this.items[key]).trim();
        }

But that's not quite satisfying.

解决方案

The following code works fine in typescript playground:

interface IGulpInjectable extends String 
{ 
    gulp_inject: string;
}

class Cache 
{
    private items: { [key: string] : IGulpInjectable };


    constructor() 
    {

        let item1 = new String("   123   ");
        item1["gulp_inject"] = "file1.html";

        let item2 = new String("   4556  ");
        item2["gulp_inject"] = "file2.html";

        this.items = {
            "item1": <IGulpInjectable>item1,
            "item2": <IGulpInjectable>item2
        }
    }

    getItem(key: string)
    {
        return this.items[key];
    }
}

let c = new Cache();
let i = c.getItem("item1");
console.log(i.trim()); //output '123'
console.log(i.gulp_inject); //output 'file1.html'

Link: typescript playground

Hope this helps.

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