来自其他Gulp任务的Gulp任务？ [英] Gulp tasks from within other Gulp tasks?

问题描述

  gulp.task（'
 
）我有一个Gulp构建任务，由其他构建任务组成： build'，['build-html'，'build-css'，'build-js'，'build-images']）; 
  

我最讨厌的是 build



 启动'build-html'... 
在1 s后完成'build-html'
开始'build-css'... 
在1 s后完成'build-css'
开始'build-js'... 
在1秒后完成'build-js'
开始'构建图像'... 
在1秒后完成'构建图像'
开始'构建'... 
在1 ms后完成'build'
  

现在很明显， build 根本不应该运行，直到它的依赖关系完成，所以它按预期工作。但是这导致控制台说 build 只花了1毫秒，实际上它应该说花了4秒钟，因为它的所有依赖关系花了很长时间。如果看起来像这样：



 启动'build'... 
启动'build- html'... 
 1 s后完成'build-html'
开始'build-css'... 
 1 s后完成'build-css'
开始' build-js'... 
在1 s后完成'build-js'
开始'build-images'... 
在1 s后完成'build-images'
 4 s后完成'build'
  

注意 build 是开始的第一件事，然后所有依赖运行，然后 build 完成。



所以我想知道的是，我可以从 build 中一次调用每个任务，而不是使用任务依赖关系。 code>任务？如果是这样，我用什么命令来做到这一点？

这是一个坏主意吗？是否有更好的解决方案来解决这个问题？我猜你可以使用 .com / OverZealous / run-sequencerel =nofollow> runSequence 插件来做你想做的事。

因为你的 build 任务是启动所有 build - * 任务，并且没有特定的顺序，这可以如下所示：

  var rs = require（'run-sequence'）; 
 
 gulp.task（'build'，function（cb）{
 rs（['build-css'，'build-html'，'build-js'，'build-images ']，cb）; 
}）; 
  

I have a Gulp build task that is made up of other build tasks similar to this:

gulp.task('build', ['build-html', 'build-css', 'build-js', 'build-images']);

The thing I hate about this is that the build task doesn't run until after the dependencies are finished:

Starting 'build-html'...
Finished 'build-html' after 1 s
Starting 'build-css'...
Finished 'build-css' after 1 s
Starting 'build-js'...
Finished 'build-js' after 1 s
Starting 'build-images'...
Finished 'build-images' after 1 s
Starting 'build'...
Finished 'build' after 1 ms

Now obviously, build is not supposed to run at all until it's dependencies are finished, so it's working as expected. But this results in the console saying build took only 1 ms when in reality it should say it took 4 seconds, since all it's dependencies took that long. It would be nice if it looked something like this:

Starting 'build'...
Starting 'build-html'...
Finished 'build-html' after 1 s
Starting 'build-css'...
Finished 'build-css' after 1 s
Starting 'build-js'...
Finished 'build-js' after 1 s
Starting 'build-images'...
Finished 'build-images' after 1 s
Finished 'build' after 4 s

Notice how build is the first thing that "starts", then all the dependencies run, then build finishes.

So what I'm wondering, instead of using task dependencies, can I just call each task one at a time from within the build task? If so, what command do I use to do this?

Is this a bad idea? Is there a better solution to this problem?

解决方案

I guess you could use the runSequence plugin to do what you want.

Since the only purpose of your build task is to launch all the build-* tasks with no specific order, this can look like:

var rs = require('run-sequence');

gulp.task('build', function (cb) {
  rs(['build-css', 'build-html', 'build-js', 'build-images'], cb);
});

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