gulp sourcemaps不能编写预期的源代码 [英] gulp sourcemaps not writing expected sourcemap

问题描述

以下是任务：

Here is the task:

dev.assets.sass = [
            'client/modules/*[!public]*/scss/*.scss'
        ];

gulp.task('sass', function () {
    gulp.src(dev.assets.sass)
        .pipe(sourcemaps.init())
        .pipe(sass({outputStyle: 'compressed'}).on('error', sass.logError))
        .pipe(concat('application.min.css'))
        .pipe(sourcemaps.write('./maps'))
        .pipe(gulp.dest('./client/build'));
});

问题是源图如下所示：

{"version":3,"sources":["../../stdin"]....

这不是我所期望的。我想要一些类似bootstrap的东西，在Chrome开发者中，一种风格被映射回原来的较少源代码。我的源代码映射回stdin，我认为这是sass管道的结果。我认为gulp-sourcemaps只是为最后一个操作创建映射...

which is not what I expected. I would like something similar to bootstrap, where, in the chrome developer a style is mapped back to its original less source. My sourcemaps are just mapping back to stdin which I assume is the result of the sass pipe. I think gulp-sourcemaps is only creating the map for the last operation...

推荐答案

您需要更新 gulp-sass 到版本 2.1.1 。这是 gulp-sass 中的一个错误，该错误已在最新版本中修复。

You need to update gulp-sass to version 2.1.1. This was a bug in gulp-sass that was fixed with the latest release.

来源： https://github.com/dlmanning/gulp-sass/issues/394

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