如何处理配置单元中的XML文件 [英] How to handle XML file in hive

问题描述

如何在配置单元中处理这个XML文件，我只希望输出USERNAME和PASSWORD

><？XML version ='1.0'？>
< DATA>
< USER USERNAME =ABCFIRSTNAME =RAJLASTNAME =KUMARPASSWORD =123/>
< USER USERNAME =DEFFIRSTNAME =VENKATLASTNAME =BALAJIPASSWORD =123/>
< / DATA>

  CREATE TABLE user_xml（USERNAME字符串，PASSWORD字符串）
 ROW FORMAT SERDE'com.ibm.spss.hive.serde2.xml.XmlSerDe'
 WITH SERDEPROPERTIES（
column.xpath.USERNAME=/ DATA / USER / USERNAME / text（），
column.xpath.PASSWORD=/ DATA / USER / PASSWORD / text（）
）存储为
 INPUTFORMAT'com.ibm。 spss.hive.serde2.xml.XmlInputFormat'
 OUTPUTFORMAT'org.apache.hadoop.hive.ql.io.IgnoreKeyTextOutputFormat'
 TBLPROPERTIES（xmlinput.start=< DATA，xmlinput .END = < / DATA>中）; 
  

解决方案

最后得到输出请参考 https://community.hortonworks.com/articles/972/hive-and-xml- pasring.html

How to handle this XML file in hive, I want only USERNAME and PASSWORD in output

<?XML version=’1.0′ ?>
<DATA>
    <USER USERNAME="ABC" FIRSTNAME="RAJ" LASTNAME="KUMAR" PASSWORD="123" />
    <USER USERNAME="DEF" FIRSTNAME="VENKAT" LASTNAME="BALAJI" PASSWORD="123" />
</DATA>

CREATE TABLE user_xml(USERNAME string,PASSWORD string)
    ROW FORMAT SERDE 'com.ibm.spss.hive.serde2.xml.XmlSerDe'
    WITH SERDEPROPERTIES ( 
        "column.xpath.USERNAME"="/DATA/USER/USERNAME/text()",
        "column.xpath.PASSWORD"="/DATA/USER/PASSWORD/text()"
    ) STORED AS
        INPUTFORMAT 'com.ibm.spss.hive.serde2.xml.XmlInputFormat'
        OUTPUTFORMAT 'org.apache.hadoop.hive.ql.io.IgnoreKeyTextOutputFormat'
        TBLPROPERTIES ("xmlinput.start"="<DATA","xmlinput.end"="</DATA>");

解决方案

Finally got output please refer https://community.hortonworks.com/articles/972/hive-and-xml-pasring.html

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