在Ruby中从哈希数组中删除哈希 [英] Deleting a hash from array of hashes in Ruby

问题描述

  [{k1=>v1，k2 =75.1％}，{k1=>v2，k2=> -  NA-}，{k1=>v3，k2=> ;5.1％}] 
  

现在，我想先检查数组是否包含散列键k1，其值v3。如果是，那么我想从数组中删除该散列。

结果应该是：

  [{k1= >v1，k2=>75.1％}，{k1=>v2，k2=> -  NA-}] 
  

解决方案

使用 Array＃delete_if ：

  arr = [{k1=>v1，k2=>75.1％}，{k1=>v2，k2= > -  NA-}，{k1=>v3，k2=>5.1％}] 
 
 arr.delete_if {| h | h [k1] ==v3} 
＃=> [{k1=>v1，k2=>75.1％}，{k1=>v2，k2=> -  NA-}] $ b  

如果没有匹配条件的哈希，数组保持不变。

I have an array of hashes as following:

[{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}, {"k1"=>"v3", "k2"=>"5.1%"}]

Now, I want to first check whether the array contains a hash with key "k1" with value "v3". If yes, then I want to delete that hash from the array.

The result should be:

[{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}]

解决方案

Use Array#delete_if:

arr = [{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}, {"k1"=>"v3", "k2"=>"5.1%"}]

arr.delete_if { |h| h["k1"] == "v3" }
#=> [{"k1"=>"v1", "k2"=>"75.1%"}, {"k1"=>"v2", "k2"=>"-NA-"}]

If there is no hash matching the condition, the array is left unchanged.

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