如何递归地从（YAML）散列中删除所有具有空值的键？ [英] How to recursively remove all keys with empty values from (YAML) hash?

问题描述

我一直试图摆脱我的YAML文件中具有空（空）值或空散列值的所有散列键。

这以前的帖子帮助我得到它几乎正确，但递归只要有足够深的嵌套，一行代码就会留下我的YAML dump。

我非常感谢这方面的帮助。感谢！

  proc = Proc.new {| k，v | （v.kind_of？（Hash）&&！v.empty？）？ （v.delete_if（& proc）; nil）：v.blank？ } 
 
 hash = {x=> {m=> {n=> {}}}，'y'=> 'content'} 
 hash.delete_if（& proc）
  

实际输出

  {x=> {m=> {}}，y=>content} 
  

所需输出

  {y=>content} 
  

解决方案

  class Hash 
 def delete_blank 
 delete_if {| k，v | v.empty？或者v.instance_of？（哈希）&& v.delete_blank.empty？} 
 end 
 end 
 
 p hash.delete_blank 
＃=> {y=>content} 
  

I have been trying to get rid of all hash keys in my YAML file that have empty (blank) values or empty hashes as values.

This earlier post helped me to get it almost right, but the recursive one-liner leaves my YAML dump with empty hashes whenever there is sufficiently deep nesting.

I would really appreciate any help on this. Thanks!

proc = Proc.new { |k, v| (v.kind_of?(Hash) && !v.empty? ) ? (v.delete_if(&proc); nil) : v.blank? }

hash = {"x"=>{"m"=>{"n"=>{}}}, 'y' => 'content'}
hash.delete_if(&proc)

Actual output

 {"x"=>{"m"=>{}}, "y"=>"content"} 

Desired output

{"y"=>"content"}

解决方案

class Hash
  def delete_blank
    delete_if{|k, v| v.empty? or v.instance_of?(Hash) && v.delete_blank.empty?}
  end
end

p hash.delete_blank
# => {"y"=>"content"}

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