Ruby：一次构建一个来自字符串和两个数组值的散列 [英] Ruby: Building a hash from a string and two array values at a time

问题描述

  hash = {} 
 
字符串= [one，two，three] 
 
 array = [1，2，3，4，5，6] 
  pre> 
 
 
以便我最终得到： 
 
 
  hash = { one=> [1,2]，
two=> [3,4]，
three=> [5，6]} 
  
我试过了： 
 
 
  strings.each do | string | 
 array.each_slice（2）do | numbers | 
 hash [string] = [numbers [0]，numbers [1]] 
 end 
 end 
  
但是，收益率：
 
 
  hash = {one=> [5,6]，two=> [5,6]，三=> [5,6]} 
  
我知道它为什么会这样做（嵌套循环），但我不知道知道如何实现我在找的东西。
解决方案
如果你想要一个单行的话：
  hash = Hash [strings.zip（array.each_slice（2））] 
  
例如：
 
 
 >> strings = [one，two，three] 
>> array = [1，2，3，4，5，6] 
>> hash = Hash [strings.zip（array.each_slice（2））] 
 => {one=> [1,2]，two=> [3,4]，three=> [5,6]} 
  pre> 
I'm trying to build a hash with:
hash = {}

strings = ["one", "two", "three"]

array = [1, 2, 3, 4, 5, 6]
so that I end up with:
hash = { "one" => [1, 2] ,
         "two" => [3, 4] ,
         "three" => [5, 6] }
I have tried:
strings.each do |string|
  array.each_slice(2) do |numbers|
    hash[string] = [numbers[0], numbers[1]]
  end
end
But that yields:
hash = { "one" => [5,6] , "two" => [5,6], "three" => [5,6] }
I know why it does this (nested loops) but I don't know how to achieve what I'm looking for.
解决方案
If you want a one-liner:
hash = Hash[strings.zip(array.each_slice(2))]
For example:
>> strings = ["one", "two", "three"]
>> array = [1, 2, 3, 4, 5, 6]
>> hash = Hash[strings.zip(array.each_slice(2))]
=> {"one"=>[1, 2], "two"=>[3, 4], "three"=>[5, 6]}


                        
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