如何比较java中的两个hashmaps? [英] How to compare two hashmaps in java?
问题描述
我有两个散列贴图,如下所示:
1。============ =员工=================
关键:1_10:价值:13/04/2012
关键:1_11:价值:18/04/2012
Key:1_12:Value:19/04/2012
Key:1_14:Value:23/04/2012
Key:1_13:Value:20/04 / 2012
Key:1_16:Value:25/04/2012
Key:1_1:Value:02/04/2012
Key:1_15:Value:24/04/2012
Key:1_18:Value:27/04/2012
Key:1_3:Value:04/04/2012
Key:1_17:Value:26/04/2012
Key:1_2:价值:03/04/2012
Key:1_5:Value:06/04/2012
Key:1_19:Value:30/04/2012
Key:1_4:Value:05/04 / 2012
Key:1_7:Value:10/04/2012
Key:1_6:Value:09/04/2012
Key:1_9:Value:12/04/2012
Key:1_8:Value:11/04/2012
2。=============工作日============= ====
Key:27:Value:27/4/2012
Key:02:Value:02/4/2012
Key:26:Value:26 / 4/2012
钥匙:19:价值:19/4/2012
关键:11:价值:11/4/2012
关键:04:价值:04/4/2012
关键:30:价值: 30/4/2012
Key:06:Value:06/4/2012
Key:13:Value:13/4/2012
Key:09:Value:09/4/2012
钥匙:03:价值:03/4/2012
钥匙:23:价值:23/4/2012
钥匙:20:价值:20/4/2012
钥匙:16:Value:16/4/2012
Key:10:Value:10/4/2012
Key:18:Value:18/4/2012
Key:25:Value: 25/4/2012
关键:17:价值:17/4/2012
关键:12:价值:12/4/2012
关键:24:价值:24/4/2012
Key:05:Value:05/4/2012
键不一样,但值是相同的,有时价值不同。
我想找出 workingdaymap
$ b
if(!employeeMap.containsValue(workingdayMap.get(wKey))){
// tak e在workingdayMap中存在的employeeMap中不存在的值,但是它在workingdayMap
}
中存在
您可以帮我解决这个问题吗?
问候
Tony
下面是代码完美的作用,比较失败的原因是map值不同。
关键:27:价值:27/4/2012,关键:1_18:价值:27/04/2012
如果我们看到日期,则可以清楚地看到差异。 2012年4月27日
与 2012年4月27日
不同,因为我将它存储为一个字符串。
Iterator< Map.Entry< String,String>> holyDayiterator = workingdayMap.entrySet()。iterator();
while(holyDayiterator.hasNext()){
Map.Entry holiDayEntry = holyDayiterator.next(); $!$ b $ if(!employeeMap.containsValue((holiDayEntry.getValue()))){
System.out.println(works perfect);
}
感谢您们的支持和对投票结果负责的人。
:)
Tony
I have two hash maps like the following:
1.=============Employee=================
Key : 1_10 : Value : 13/04/2012
Key : 1_11 : Value : 18/04/2012
Key : 1_12 : Value : 19/04/2012
Key : 1_14 : Value : 23/04/2012
Key : 1_13 : Value : 20/04/2012
Key : 1_16 : Value : 25/04/2012
Key : 1_1 : Value : 02/04/2012
Key : 1_15 : Value : 24/04/2012
Key : 1_18 : Value : 27/04/2012
Key : 1_3 : Value : 04/04/2012
Key : 1_17 : Value : 26/04/2012
Key : 1_2 : Value : 03/04/2012
Key : 1_5 : Value : 06/04/2012
Key : 1_19 : Value : 30/04/2012
Key : 1_4 : Value : 05/04/2012
Key : 1_7 : Value : 10/04/2012
Key : 1_6 : Value : 09/04/2012
Key : 1_9 : Value : 12/04/2012
Key : 1_8 : Value : 11/04/2012
2.=============Working day=================
Key : 27 : Value : 27/4/2012
Key : 02 : Value : 02/4/2012
Key : 26 : Value : 26/4/2012
Key : 19 : Value : 19/4/2012
Key : 11 : Value : 11/4/2012
Key : 04 : Value : 04/4/2012
Key : 30 : Value : 30/4/2012
Key : 06 : Value : 06/4/2012
Key : 13 : Value : 13/4/2012
Key : 09 : Value : 09/4/2012
Key : 03 : Value : 03/4/2012
Key : 23 : Value : 23/4/2012
Key : 20 : Value : 20/4/2012
Key : 16 : Value : 16/4/2012
Key : 10 : Value : 10/4/2012
Key : 18 : Value : 18/4/2012
Key : 25 : Value : 25/4/2012
Key : 17 : Value : 17/4/2012
Key : 12 : Value : 12/4/2012
Key : 24 : Value : 24/4/2012
Key : 05 : Value : 05/4/2012
Keys are not same but the values are same and sometime the values are not same.
i want to find out the value which are not present in employeemap
when comparing with workingdaymap
if (!employeeMap.containsValue(workingdayMap.get(wKey))) {
//take the value which is not present in employeeMap which is present in workingdayMap
}
but it gives me null from employeeMap.
Could you please help me to solve this?
Regards Tony
below is the code which works perfectly, the reason why the comparison failed is the map value is different .
Key : 27 : Value : 27/4/2012, Key : 1_18 : Value : 27/04/2012
if we see the dates, the difference is clearly seen. 27/4/2012
is different from 27/04/2012
since i stored it as a string.
Iterator<Map.Entry<String,String>> holyDayiterator = workingdayMap.entrySet().iterator();
while (holyDayiterator.hasNext()) {
Map.Entry holiDayEntry = holyDayiterator.next();
if(!employeeMap.containsValue((holiDayEntry.getValue()))){
System.out.println("works perfect");
}
Thanks guys for your support and people who have gave down vote also.
:) Tony
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