如何实现在C计数HashMap？ [英] how to implement counting hashmap in c?

问题描述

我有6个常量字符串（每个5个字母）

我得到了一小部分词汇（在这6个词中）。

我想统计每个单词出现的次数。

如何在C中实现它？

我曾尝试过：

  char searchEngineNames [6] [ 5] = {waze_，faceb，fours，googl，
fueli，yello}; 
 $ b $ static foo（const char * res_name，int success，void * context，char * last_modified）{
 if（success）{
 for（int i = 0; i< ; 6; i ++）
 {
 char substringFiveChars [6]; 
 
 strncpy（substringFiveChars，res_name，5）; 
 
 char substringFiveChars [6]; 
 
 substringFiveChars [5] = 0; 
 
 if（strcmp（searchEngineNames [i]，substringFiveChars）== 0）
 {
 ... 
} 
 .. 
 } 
  

例如：

wooo _，wooo _，faceb，wooo _，google

我最终会得到：

 wooo_3次
 
faceb1次
 
google1次
 
fours 0次
 
fuelil0次
 
yello0次
  

解决方案

我使用2个数组而不是1个。

  char searchEngineNames [6] [5] = {wooo_，faceb，fours，google，
fuelil，yello}; 
 
 int searchEngineCounts [6] = {0,0,0,0,0,0}; 
 
 
 
 static void foo（const char * res_name，
 int success，void * context，char * last_modified）{
 if（success）{ 
 
 int i = 0; 
 for（i; i <6; i ++）{
 char substringFiveChars [6]; 
 
 strncpy（substringFiveChars，res_name + 7，5）; 
 
 substringFiveChars [5] = 0; 
 
 if（strcmp（searchEngineNames [i]，substringFiveChars）== 0）{
 searchEngineCounts [i] ++; 
 
 if（searchEngineCounts [i] <3）{
 
 ... 
} 
} 
} 
 
} 
} 
  

I have 6 const strings (5 letters each)

I get a stream of few words (out of these 6 words).

I want to count how many occurrences were out of each word.

How can I implement it in C ?

I have tried:

  char searchEngineNames[6][5] = { "waze_", "faceb", "fours", "googl",
        "fueli", "yello" };

    static void foo(const char* res_name, int success, void *context, char *last_modified) {
        if (success){
                for (int i=0; i<6; i++)
                {
                    char substringFiveChars[6];

                    strncpy(substringFiveChars, res_name, 5);

                            char substringFiveChars[6]; 

                            substringFiveChars[5] = 0;

                    if (strcmp(searchEngineNames[i],substringFiveChars) == 0)
                    {
                    ... 
                    }
    ..
                }

for example for this stream:

"wooo_","wooo_","faceb","wooo_","google"

I will eventually get:

"wooo_" 3 times

"faceb" 1 times 

"google" 1 times 

"fours" 0 times

"fuelil" 0 times

"yello" 0 times

解决方案

I use 2 arrays instead of 1.

char searchEngineNames[6][5] = { "wooo_", "faceb", "fours", "google",
        "fuelil", "yello" };

int searchEngineCounts[6] = {0,0,0,0,0,0};



static void foo(const char* res_name,
        int success, void *context, char *last_modified) {
    if (success) {

        int i = 0;
        for (i; i < 6; i++) {
            char substringFiveChars[6];

            strncpy(substringFiveChars, res_name+7, 5);

            substringFiveChars[5] = 0;

            if (strcmp(searchEngineNames[i], substringFiveChars) == 0) {
                searchEngineCounts[i]++;

                if (searchEngineCounts[i] < 3) {

...
                }
            }
        }

    }
}

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