PopupWindow - 辞退当外界点击 [英] PopupWindow - Dismiss when clicked outside

问题描述

我有我的活性PopupWindow，事情是我PopupWindow还表示，即使当我跟我的互动活动（比如滚动我的列表）。我可以通过我的列表中滚动和PopupWindow仍然存在。

I have a PopupWindow on my activity, the thing is my PopupWindow still shows even when I'm interacting with my activity (say scrolling on my list). I can scroll through my list and the PopupWindow is still there.

当我触摸/滚动​​/点击的/ etc这不是PopupWindow在屏幕上，我想驳回PopupWindow我想实现的是。就像如何菜单的工作原理。如果您单击菜单之外，菜单将被开除。

What I want to achieve is when I'm touching/scrolling/clicking/etc on the screen which is not the PopupWindow, I want to dismiss the PopupWindow. Just like how a menu works. If you clicked outside of the menu, the menu will be dismissed.

我已经试过 setOutsideTouchable（真）但不会关闭该窗口。谢谢你。

I've tried setOutsideTouchable(true) but it won't dismiss the window. Thanks.

推荐答案

请尝试在PopupWindow，如果你在它之外触及应该关闭该窗口中设置setBackgroundDrawable。

Please try to set setBackgroundDrawable on PopupWindow that should close the window if you touch outside of it.

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