如何比较Haskell中的两个列表? [英] How to compare two lists in Haskell?
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问题描述
例子:
[1,2 ] = [2,1]
我试过全部(flip elem [1,2,3])[ 2,1]
,但这会返回 true
...
谢谢。 / p>
解决方案
类似这样的事情?
import Data.List(sort)
areEqual ab = sort a == sort b
OUTPUT:
* Main> areEqual [1,2] [2,1]
True
In Haskell, how can you compare two lists to check if they are equal? Also the order shouldn't matter.
Example:
[1,2] = [2,1]
I tried all (flip elem [1,2,3]) [2,1]
, but this returns true
...
Thanks.
解决方案
Something like this?
import Data.List (sort)
areEqual a b = sort a == sort b
OUTPUT:
*Main> areEqual [1,2] [2,1]
True
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