从箭头符号转换 [英] Convert from arrow notation
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问题描述
counter :: ArrowCircuit a => Bool Int
counter = proc reset - >做
rec输出< - returnA - <如果重置,那么0 else else
next< - 延迟0 - <输出+ 1
returnA - <输出
有人可以告诉我如何将其转换回Haskell2010而不使用箭头符号吗?
解决方案
{ - |
+ --------- +
> Bool> --------------> |
| > ------------------>诠释>
+ --------- + | arr f |
/ ---->延迟0> - > > --------- \
| + --------- + | | |
| + --------- + |
| |
\ -------------------------------------- /
- }
counter':: ArrowCircuit a => Bool Int
counter'= loop $ second(delay 0)>>> arr f
其中
f(reset,next)= let output = if reset 0 then else next
next'= output + 1
in(output,next')
递归 rec
部分使用环
。使用下一个
((code>))将 reset
转换为输出
的内部部分并产生新的下一个
值)只是一个具有两个输入和两个输出的纯函数。
I'm still trying to get a hang of the parallels between arrow notation and the semantics of the Arrow typeclasses defined in Haskell. In particular, this question seems to have a very canonical example of a small counter written with arrow notation:
counter :: ArrowCircuit a => a Bool Int
counter = proc reset -> do
rec output <- returnA -< if reset then 0 else next
next <- delay 0 -< output+1
returnA -< output
Can someone show me how to convert this back into Haskell2010 without arrow notation?
解决方案
{- |
+---------+
>Bool>--------------> |
| >------------------>Int>
+---------+ | arr f |
/----> delay 0 >---> >---------\
| +---------+ | | |
| +---------+ |
| |
\--------------------------------------/
-}
counter' :: ArrowCircuit a => a Bool Int
counter' = loop $ second (delay 0) >>> arr f
where
f (reset, next) = let output = if reset then 0 else next
next' = output + 1
in (output, next')
The recursive rec
part is implemented using loop
. The inner part that converts reset
to output
using next
(and producing new next
value) is just a pure function with two inputs and two outputs.
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