猫多个文件，但包括文件名作为标题 [英] cat multiple files but include filename as headers

问题描述

我想将多个文本文件连接成终端中的一个大文件。我知道我可以使用cat命令来做到这一点。但是，我希望每个文件的文件名位于该文件的数据转储之前。任何人都知道如何做到这一点？

我现在有什么：

  file1.txt = bluemoongoodbeer 
 
 file2.txt = awesomepossum 
 
 file3.txt = hownowbrowncow 
 
 cat file1.txt file2.txt file3.txt 
  

所需输出：

  file1 
 
 bluemoongoodbeer 
 
 file2 
 
 awesomepossum 
 
 file3 
 
 hownowbrowncow 
  

解决方案

正在寻找相同的东西，这提示：

  tail -n +1 file1.txt file2.txt file3.txt 
  
 
 $ b 
输出： 
 
 
  ==> ; file1.txt< == 
< file1.txt的内容> 
 
 ==> file2.txt< == 
< file2.txt的内容> 
 
 ==> file3.txt< == 
< file3.txt的内容> 
  
如果只有一个文件，那么标题将不会被打印。如果使用GNU utils，您可以使用 -v 来始终打印标题。
 
I would like to concatenate a number of text files into one large file in terminal. I know I can do this using the cat command. However, I would like the filename of each file to precede the "data dump" for that file. Anyone know how to do this?

what I currently have:
file1.txt = bluemoongoodbeer

file2.txt = awesomepossum

file3.txt = hownowbrowncow

cat file1.txt file2.txt file3.txt
desired output:
file1

bluemoongoodbeer

file2

awesomepossum

file3

hownowbrowncow

解决方案
Was looking for the same thing, and found this to suggest:
tail -n +1 file1.txt file2.txt file3.txt
Output:
==> file1.txt <==
<contents of file1.txt>

==> file2.txt <==
<contents of file2.txt>

==> file3.txt <==
<contents of file3.txt>
If there is only a single file then the header will not be printed. If using GNU utils, you can use -v to always print a header.

                        
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