Python urllib2响应头 [英] Python urllib2 Response header

问题描述

我试图提取URL请求的响应头。当我使用firebug分析URL请求的响应输出时，它会返回：

I'm trying to extract the response header of a URL request. When I use firebug to analyze the response output of a URL request, it returns:

Content-Type text/html

然而，当我使用python代码时：

However when I use the python code:

urllib2.urlopen(URL).info()

结果输出返回：

Content-Type: video/x-flv

我对python和一般的web编程都很陌生;任何有用的见解，非常感谢。此外，如果需要更多信息，请让我知道。

I am new to python, and to web programming in general; any helpful insight is much appreciated. Also, if more info is needed please let me know.

感谢您阅读本文

推荐答案

尝试像Firefox那样请求。您可以在Firebug中看到请求标题，因此将它们添加到您的请求对象中：

Try to request as Firefox does. You can see the request headers in Firebug, so add them to your request object:

import urllib2

request = urllib2.Request('http://your.tld/...')
request.add_header('User-Agent', 'some fake agent string')
request.add_header('Referer', 'fake referrer')
...
response = urllib2.urlopen(request)
# check content type:
print response.info().getheader('Content-Type')

还有HTTPCookieProcessor，它可以让它变得更好，但我不认为大多数情况下你都需要它。看看python的文档：

There's also HTTPCookieProcessor which can make it better, but I don't think you'll need it in most cases. Have a look at python's documentation:

http ：//docs.python.org/library/urllib2.html

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