使用比较运算符来表示十六进制值 [英] Using Comparison Operators for Hex Values

问题描述

我想创建一个函数，只有当十六进制值表示大写或小写字母时，即十六进制代码在20和7A之间时，才执行某个任务。有没有一种方法可以在Python中进行逻辑上等价的语句：

 如果a> = 20且a < = 7A：执行的东西
  

？我只是在它前面抛出一个0x并发生魔法？

解决方案

是的...你只是抛出一个0x，它变成了数字....

或 int（7A，16）== 0x7A

0x20 <= a <= 0x7A 你也可以像这样链接比较运算符（大致转换为是在val1和val2之间）

I want to create a function that performs a certain task only when a hex value indicates an upper or lower case letter, i.e., when the hex code is between 20 and 7A. Is there a way to make a statement in python that is logically equivalent to:

if a >= 20 and a <= 7A: perform stuff

? Do I just throw a 0x in front of it and magic happens?

解决方案

yes ... you just throw a 0x and it becomes numeric ....

or int("7A",16) == 0x7A

0x20 <= a <= 0x7A you can also chain comparison operators like this (which translates roughly to "is a between val1 and val2")

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