获取联系人姓名给出的Andr​​oid电话号码 [英] Get contact name given a phone number in Android

问题描述

我想给出的联系电话号码检索联系人姓名。我做了应该适用于所有的API版本的函数，通过我不能使它在1.6工作，我看不出这个问题，也许有人能发现吗？

请注意，我把它换成了API常量字符串，所以我没有去precated警告的问题。

 公共字符串getContactName（最后弦乐phoneNumber的）
{
    乌里URI;
    的String []投影;

    如果（Build.VERSION.SDK_INT＆GT; = 5）
    {
        URI = Uri.parse（内容：//com.android.contacts/phone_lookup）;
        投影=新的String [] {DISPLAY_NAME};
    }
    其他
    {
        URI = Uri.parse（内容：//联系人/手机/过滤器）;
        投影=新的String [] {姓名};
    }

    URI = Uri.withAppendedPath（URI，Uri.en code（phoneNumber的））;
    光标光标= this.getContentResolver（）查询（URI，投影，NULL，NULL，NULL）;

    字符串联系人姓名=;

    如果（cursor.moveToFirst（））
    {
        CONTACTNAME = cursor.getString（0）;
    }

    cursor.close（）;
    光标= NULL;

    返回联系人姓名;
}
 

解决方案

使用，而不是比较SDK版本的思考。

 公共字符串getContactName（最后弦乐phoneNumber的）
{
    乌里URI;
    的String []投影;
    mBaseUri = Contacts.Phones.CONTENT_FILTER_URL;
    投影=新的String [] {android.provider.Contacts.People.NAME};
    尝试 {
        类＆LT;＆GT; C =的Class.forName（android.provider.ContactsContract $ PhoneLookup）;
        mBaseUri =（URI）c.getField（CONTENT_FILTER_URI）获得（mBaseUri）。
        投影=新的String [] {DISPLAY_NAME};
    }
    赶上（例外五）{
    }


    URI = Uri.withAppendedPath（mBaseUri，Uri.en code（phoneNumber的））;
    光标光标= this.getContentResolver（）查询（URI，投影，NULL，NULL，NULL）;

    字符串联系人姓名=;

    如果（cursor.moveToFirst（））
    {
        CONTACTNAME = cursor.getString（0）;
    }

    cursor.close（）;
    光标= NULL;

    返回联系人姓名;
}
 

I am trying to retrieve contact names given the contact phone number. I made a function that should work in all API versions, by I can't make it work in 1.6 and I can't see the problem, maybe someone can spot it?

Note that, I've replaced the API constants for strings so I don't have deprecated warning problems.

public String getContactName(final String phoneNumber) 
{  
    Uri uri;
    String[] projection;

    if (Build.VERSION.SDK_INT >= 5)
    {
        uri = Uri.parse("content://com.android.contacts/phone_lookup");
        projection = new String[] { "display_name" };
    }
    else
    { 
        uri = Uri.parse("content://contacts/phones/filter");
        projection = new String[] { "name" }; 
    } 

    uri = Uri.withAppendedPath(uri, Uri.encode(phoneNumber)); 
    Cursor cursor = this.getContentResolver().query(uri, projection, null, null, null); 

    String contactName = "";

    if (cursor.moveToFirst()) 
    { 
        contactName = cursor.getString(0);
    } 

    cursor.close();
    cursor = null;

    return contactName; 
}

解决方案

Use reflections instead of comparing sdk version.

public String getContactName(final String phoneNumber) 
{  
    Uri uri;
    String[] projection;
    mBaseUri = Contacts.Phones.CONTENT_FILTER_URL;
    projection = new String[] { android.provider.Contacts.People.NAME }; 
    try {
        Class<?> c =Class.forName("android.provider.ContactsContract$PhoneLookup");
        mBaseUri = (Uri) c.getField("CONTENT_FILTER_URI").get(mBaseUri);
        projection = new String[] { "display_name" };
    } 
    catch (Exception e) {
    }


    uri = Uri.withAppendedPath(mBaseUri, Uri.encode(phoneNumber)); 
    Cursor cursor = this.getContentResolver().query(uri, projection, null, null, null); 

    String contactName = "";

    if (cursor.moveToFirst()) 
    { 
        contactName = cursor.getString(0);
    } 

    cursor.close();
    cursor = null;

    return contactName; 
}

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