如何启动电源按钮preSS应用程序 [英] how to start the app on power button press

问题描述

我要开始我的应用程序，当用户preSS的电源按钮。我米以下的<一个href="http://stackoverflow.com/questions/8940922/activate-an-application-when-a-power-button-is-clicked">This code 但它没有显示任何登录和烤面包片。

I want to start my app when a user press the power button. I m following This code but its not showing any Log and toast.

这是我的完整的code。

here is my complete code.

MyReceiver.java

import android.content.BroadcastReceiver;
   import android.content.Context;
   import android.content.Intent;
   import android.util.Log;
   import android.widget.Toast;

   public class MyReceiver extends BroadcastReceiver {

@Override
public void onReceive(Context context, Intent intent) {

    // TODO Auto-generated method stub

    Log.v("onReceive", "Power button is pressed.");

    Toast.makeText(context, "power button clicked", Toast.LENGTH_LONG)
            .show();

    // perform what you want here

}

}

menifest文件

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.powerbuttontest"
android:versionCode="1"
android:versionName="1.0" >

<uses-sdk
    android:minSdkVersion="8"
    android:targetSdkVersion="17" />

<application
    android:allowBackup="true"
    android:icon="@drawable/ic_launcher"
    android:label="@string/app_name"
    android:theme="@style/AppTheme" >
    <activity
        android:name="com.example.powerbuttontest.MainActivity"
        android:label="@string/app_name" >
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />

            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>
    <receiver android:name=".MyReceiver" >
        <intent-filter>
            <action android:name="android.intent.action.SCREEN_OFF" >
            </action>
            <action android:name="android.intent.action.SCREEN_ON" >
            </action>
            <action android:name="android.intent.action.ACTION_POWER_CONNECTED" >
            </action>
            <action android:name="android.intent.action.ACTION_POWER_DISCONNECTED" >
            </action>
            <action android:name="android.intent.action.ACTION_SHUTDOWN" >
            </action>
        </intent-filter>
    </receiver>
</application>
</manifest>

MainActivity.java

package com.example.powerbuttontest;

import android.os.Bundle;
import android.app.Activity;
import android.view.Menu;

public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.main, menu);
    return true;
}

}

• 我想我犯在我的 menifest文件中的错误。请对此看看。谢谢。
• I think i m committing a mistake in my menifest file. please have a look on this. thanks.

推荐答案

首先，与其他广泛的铸造意图，为Intent.ACTION_SCREEN_OFF和Intent.ACTION_SCREEN_ON不能在你的Andr​​oid清单申报他们！所以，你需要做，这将继续这样运行的服务

First, unlike other broad casted intents, for Intent.ACTION_SCREEN_OFF and Intent.ACTION_SCREEN_ON you CANNOT declare them in your Android Manifest! so You need to make a service which will keep on running like this

public static class UpdateService extends Service {

        @Override
        public void onCreate() {
            super.onCreate();
            // register receiver that handles screen on and screen off logic
            IntentFilter filter = new IntentFilter(Intent.ACTION_SCREEN_ON);
            filter.addAction(Intent.ACTION_SCREEN_OFF);
            BroadcastReceiver mReceiver = new Receiver();
            registerReceiver(mReceiver, filter);
        }

        @Override
        public void onStart(Intent intent, int startId) {
            boolean screenOn = intent.getBooleanExtra("screen_state", false);
            if (!screenOn) {
                // your code
            } else {
                // your code
            }
        }
}

和你的接收器可以是一些

and your receiver can be something

public class Receiver extends BroadcastReceiver {

    private boolean screenOff;

    @Override
    public void onReceive(Context context, Intent intent) {
        if (intent.getAction().equals(Intent.ACTION_SCREEN_OFF)) {
            screenOff = true;
        } else if (intent.getAction().equals(Intent.ACTION_SCREEN_ON)) {
            screenOff = false;
        }
        Intent i = new Intent(context, UpdateService.class);
        i.putExtra("screen_state", screenOff);
        context.startService(i);
    }

}

这篇关于如何启动电源按钮preSS应用程序的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！