如何遍历对象数组列表 [英] How to Iterate through List of Object arrays

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本文介绍了如何遍历对象数组列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

  Criteria crit = session 

所以现在我有一个包含一段代码的程序。 .createCriteria(Product.class);
ProjectionList projList = Projections.projectionList();
projList.add(Projections.max(price));
projList.add(Projections.min(price));
projList.add(Projections.countDistinct(description));
crit.setProjection(projList);
列表结果= crit.list();

我想迭代results.So先谢谢您提供的任何帮助/建议。在这种情况下,您将拥有一个列表,其元素是以下数组:
[maxPrice,minPrice,minPrice,计数]。

  .... 
列表< Object []> results = crit.list();

for(Object [] result:results){
Integer maxPrice =(Integer)result [0];
整数minPrice =(整数)结果[1];
长计数=(长)结果[2];
}


So right now I have a program containing a piece of code that looks like this...

Criteria crit = session.createCriteria(Product.class);
ProjectionList projList = Projections.projectionList();
projList.add(Projections.max("price"));
projList.add(Projections.min("price"));
projList.add(Projections.countDistinct("description"));
crit.setProjection(projList);
List results = crit.list();

I want to iterate results.So thank you in advance for any help/advice that is offered.

解决方案

In this case you will have a list whose elements is an array of the following: [maxPrice,minPrice,count].

....
List<Object[]> results = crit.list();

for (Object[] result : results) {
    Integer maxPrice = (Integer)result[0];
    Integer minPrice = (Integer)result[1];
    Long count = (Long)result[2];
}

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