java.lang.ClassCastException：java.lang.String不能转换为[Ljava.lang.Object [英] java.lang.ClassCastException: java.lang.String cannot be cast to [Ljava.lang.Object

问题描述

我正在运行以下查询。它显示一条错误消息。

I'm running the following query. It displays an error message. How to solve this error?

        List<Route>routeList=null;
        List<?> companyList = session.createSQLQuery ("select name " +
                                                  "from company "+
                                                  "where company_id= " + companyId).list();                 
        if(companyList.size() <= 0){
            //throw(new AppException(1018,ErrorMessages.getString("INVALID_USER_ID"))); 
        }


        routeList = new ArrayList<Route>(companyList.size());
    Route vgDetails=null;

        for (int i = 0; i < companyList.size(); i++) {

            vgDetails = new Route(); 
            Object[] row = (Object[])companyList.get(i);                                 
            vgDetails.setRouteName ((String)row[0]);                     
            routeList.add(vgDetails);       
        }                   
    session.getTransaction().commit();
        return routeList;
    }

错误的是：

The errror is:

java.lang.ClassCastException: java.lang.String cannot be cast to [Ljava.lang.Object;
    at com.claystone.server.user.UserListServiceImpl.getParticipantsDestination(UserListServiceImpl.java:902)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at com.google.gwt.user.server.rpc.RPC.invokeAndEncodeResponse(RPC.java:527)
    at com.google.gwt.user.server.rpc.RemoteServiceServlet.processCall(RemoteServiceServlet.java:166)
    at com.google.gwt.user.server.rpc.RemoteServiceServlet.doPost(RemoteServiceServlet.java:86)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:637)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
    at org.mortbay.jetty.servlet.ServletHolder.handle(ServletHolder.java:487)
    at org.mortbay.jetty.servlet.ServletHandler.handle(ServletHandler.java:362)
    at org.mortbay.jetty.security.SecurityHandler.handle(SecurityHandler.java:216)
    at org.mortbay.jetty.servlet.SessionHandler.handle(SessionHandler.java:181)
    at org.mortbay.jetty.handler.ContextHandler.handle(ContextHandler.java:729)
    at org.mortbay.jetty.webapp.WebAppContext.handle(WebAppContext.java:405)
    at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152)
    at org.mortbay.jetty.handler.RequestLogHandler.handle(RequestLogHandler.java:49)
    at org.mortbay.jetty.handler.HandlerWrapper.handle(HandlerWrapper.java:152)
    at org.mortbay.jetty.Server.handle(Server.java:324)
    at org.mortbay.jetty.HttpConnection.handleRequest(HttpConnection.java:505)
    at org.mortbay.jetty.HttpConnection$RequestHandler.content(HttpConnection.java:843)
    at org.mortbay.jetty.HttpParser.parseNext(HttpParser.java:647)
    at org.mortbay.jetty.HttpParser.parseAvailable(HttpParser.java:205)
    at org.mortbay.jetty.HttpConnection.handle(HttpConnection.java:380)
    at org.mortbay.io.nio.SelectChannelEndPoint.run(SelectChannelEndPoint.java:395)
    at org.mortbay.thread.QueuedThreadPool$PoolThread.run(QueuedThreadPool.java:488)

推荐答案

你可以写：

You can just write:

vgDetails = new Route();                                 
vgDetails.setRouteName ((String)companyList.get(i));

companyList 已经是一个字符串列表，因为您只需选择一列。

companyList is already a list of strings because you select just one column.

此外，由于Thilo的回答也表明，您可以直接将结果转换为 List< string> 而不是使用 List<？> 。

Additionally, as Thilo's answer also suggests, you can cast your result directly to a List<string> instead of using List<?>.

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