我如何使用Hibernate获取上次插入的ID [英] How can I get last inserted id using Hibernate
问题描述
我想在Hibernate中获取最后插入的值的id。
搜寻后:
Long lastId =((Long) .createSQLQuery(SELECT LAST_INSERT_ID())。uniqueResult())。longValue();
但是下面的代码给了我这个错误:
java.lang.ClassCastException:java.math.BigInteger不能转换为java.lang.Long
请分享您的想法!
解决方案
Long lastId =((BigInteger)session.createSQLQuery(SELECT LAST_INSERT_ID())。uniqueResult())。longValue();
不要忘记导入:
import java.math.BigInteger;
很清楚。它正在返回 BigInteger
而不是 long
您必须将其分配给< a href =http://docs.oracle.com/javase/7/docs/api/java/math/class-use/BigInteger.html =noreferrer> BigInteger
。并获得 longValue()
从它。
I want to fetch the last inserted value's id in Hibernate.
After search:
Long lastId = ((Long) session.createSQLQuery("SELECT LAST_INSERT_ID()").uniqueResult()).longValue();
But the following code gives me this error:
java.lang.ClassCastException: java.math.BigInteger cannot be cast to java.lang.Long
Please share your thoughts!
Solution
Long lastId = ((BigInteger) session.createSQLQuery("SELECT LAST_INSERT_ID()").uniqueResult()).longValue();
Don't forget to import:
import java.math.BigInteger;
Error is pretty clear. It's returning BigInteger
and not long
You have to assign it to a BigInteger
. And get longValue()
from it.
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