即使我指定了计数查询，也不能使用具有动态排序和/或分页的本机查询 [英] Cannot use native queries with dynamic sorting and/or pagination even if I have specified the count query

问题描述

@Query（
value =select * from paper_entry where owner is null or owner =？1，
countQuery =select count（*）from paper_entry where owner is not null或$ owner =？1，
nativeQuery = true）

$ b 页面findAll（Long userId，Pageable pageable）;

我使用mysql 5.7，spring-data-jpa 1.11.3.RELEASE。正如你所看到的，我遵循 https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#jpa.query-methods.at-query 。但是我得到了这个错误。

引起：org.springframework.data.jpa.repository.query.InvalidJpaQueryMethodException：不能在动态排序和/或分页中使用原生查询方法public abstract org.springframework.data.domain.Page com.gbdata.entry.persistence.dao.PaperEntryRepository.findAll（java.lang.Long，org.springframework.data.domain.Pageable）
at org.springframework .data.jpa.repository.query.NativeJpaQuery。（NativeJpaQuery.java:55）〜[spring-data-jpa-1.11.3.RELEASE.jar：na]
at org.springframework.data.jpa.repository .query.JpaQueryFactory.fromMethodWithQueryString（JpaQueryFactory.java:72）〜[spring-data-jpa-1.11.3.RELEASE.jar：na]
at ........

解决方案

解决没？ SQL里面加 ORDER BY？＃{＃pageable} 就可以了

  @Query（
 value =select * from paper_entry where owner is null or owner =？1 ORDER BY？＃{＃pageable}，
 countQuery =select count（*）from paper_entry where owner不是null或owner =？1 ORDER BY？＃{＃pageable}，
 nativeQuery = true）
页面findAll（Long userId，Pageable pageable）; 
  

这是问题。

@Query( value = "select * from paper_entry where owner is null or owner = ?1", countQuery = "select count(*) from paper_entry where owner is not null or owner = ?1", nativeQuery = true)

Page findAll(Long userId, Pageable pageable);

I use mysql 5.7, spring-data-jpa 1.11.3.RELEASE. As you can see, I follow the document https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#jpa.query-methods.at-query. However I got this error.

Caused by: org.springframework.data.jpa.repository.query.InvalidJpaQueryMethodException: Cannot use native queries with dynamic sorting and/or pagination in method public abstract org.springframework.data.domain.Page com.gbdata.entry.persistence.dao.PaperEntryRepository.findAll(java.lang.Long,org.springframework.data.domain.Pageable) at org.springframework.data.jpa.repository.query.NativeJpaQuery.(NativeJpaQuery.java:55) ~[spring-data-jpa-1.11.3.RELEASE.jar:na] at org.springframework.data.jpa.repository.query.JpaQueryFactory.fromMethodWithQueryString(JpaQueryFactory.java:72) ~[spring-data-jpa-1.11.3.RELEASE.jar:na] at ........

解决方案

解决没? SQL里面加 ORDER BY ?#{#pageable} 就可以了

@Query(
        value = "select * from paper_entry where owner is null or owner = ?1 ORDER BY ?#{#pageable}",
        countQuery = "select count(*) from paper_entry where owner is not null or owner = ?1 ORDER BY ?#{#pageable}",
        nativeQuery = true)
    Page findAll(Long userId, Pageable pageable);

It's duplicate of this question.

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