在Hibernate中从多个表中提取数据并将结果存储在一个bean中 [英] Fetching data from multiple tables in Hibernate and storing the result in a bean

查看:133
本文介绍了在Hibernate中从多个表中提取数据并将结果存储在一个bean中的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述



NamedQuery:

  @NamedQueries({@NamedQuery(name =Contact.findByUserId,query =select cntct.mobileNo,cntct.homeTown,cntct.city,cntct.state,cntct.country,mbr.firstName,mbr.lastName,usr。 username from Contact cntct,Member mbr,User usr where cntct.user =:user)})

@Entity
@Table(name =Contact)
public class联系{

@Id
@Column(name =CONTACT_ID)
@GeneratedValue(strategy = GenerationType.AUTO)
private contactId;

@Column(name =MOBILE_NUMBER,长度= 30)
private long mobileNo;

@Column(name =HOME_TOWN,length = 30)
private String homeTown;

@Column(name =CITY_NAME,长度= 30)
私人字符串城市;

@Column(name =STATE_NAME,length = 30)
私有字符串状态;

@Column(name =COUNTRY_NAME,长度= 30)
私人字符串国家;

以下用于激发查询和获取数据的代码。

  public ContactView getContact(long userId){
Session session = sessionFactory.openSession();
Query query = session.getNamedQuery(Contact.findByUserId);

query.setLong(user,userId);

列表<?>列表= query.list();


session.close();
返回null;
}

我面对的问题是如何映射列表数据到任何定制Bean?



或者是否有其他可行的方法?

谢谢! !

解决方案

  query.list(); 

以列表形式返回查询结果。如果查询每行包含多个结果,则结果将返回到Object []的实例中。

来源: http://docs.jboss.org/hibernate/orm/3.2/api/org/hibernate/Query.html#list()



因此,我们需要按照以下方式修改我们的代码以获得预期结果:

  List< Object []>列表= query.list(); 

for(i = 0; i< list.size(); i ++){

Object obj [] = list.get(i);

for(Object obj1:obj){
//使用适当的setter设置你的bean
}
}



其他选择:



请在hibernate中使用 ResultTransformer 结果集(复杂的选择查询)到单个实体类。

  ProdEntity prod =(ProdEntity)session.createQuery(select e.productId as pId,e.price as pPrice from Product e其中e.productId =:productId)。setParameter(productId,103).setResultTransformer(Transformers.aliasToBean(ProdEntity.class))。uniqueResult(); 


I am using Spring and Hibernate.

NamedQuery:

@NamedQueries({ @NamedQuery(name = "Contact.findByUserId", query = "select cntct.mobileNo,cntct.homeTown,cntct.city,cntct.state,cntct.country,mbr.firstName,mbr.lastName,usr.userName from Contact cntct,Member mbr,User usr where cntct.user = :user")})

@Entity
@Table(name = "Contact")
public class Contact {

@Id
@Column(name="CONTACT_ID")
@GeneratedValue(strategy=GenerationType.AUTO)  
private long contactId;

@Column(name="MOBILE_NUMBER", length=30)
private long mobileNo;

@Column(name="HOME_TOWN", length=30)
private String  homeTown;

@Column(name="CITY_NAME", length=30)
private String  city;

@Column(name="STATE_NAME", length=30)
private String  state;

@Column(name="COUNTRY_NAME", length=30)
private String  country;

The following code for firing the query and fetching the data.

public ContactView getContact(long userId) {
    Session session=sessionFactory.openSession();
    Query query=session.getNamedQuery("Contact.findByUserId");

    query.setLong("user", userId);

    List<?> list=query.list();


    session.close();
    return null;
}

The problem that I am facing is, how to map the list's data to any custom Bean?

Or is there any other viable means?

Thanks!!

解决方案

query.list();

Returns the query results as a List. If the query contains multiple results per row, the results are returned in an instance of Object[].

source: http://docs.jboss.org/hibernate/orm/3.2/api/org/hibernate/Query.html#list()

So, we need to modify our code in following way to get the intended result:

List<Object[]> list=query.list();

for(i=0;i<list.size();i++){

   Object obj[]=list.get(i);

   for(Object obj1:obj){
    //set your beans by using appropriate setters
   }    
}

Other alternative:

Please use ResultTransformer in hibernate to map the resultset(of a complex select query) to a single entity class.

 ProdEntity prod = (ProdEntity)session.createQuery("select e.productId as pId,e.price as pPrice from Product e where e.productId = :productId").setParameter("productId", 103).setResultTransformer(Transformers.aliasToBean(ProdEntity.class)).uniqueResult();

这篇关于在Hibernate中从多个表中提取数据并将结果存储在一个bean中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
相关文章
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆