如何解决：org.hibernate.HibernateException：如果没有活动事务，createCriteria无效 [英] How to Solve : org.hibernate.HibernateException: createCriteria is not valid without active transaction

问题描述

我正在学习Spring 4.0 + Hibernate 4.3集成，我对这两种技术都很陌生。解决之前我遇到错误。
$ b

applicationContext.xml

<$ p $任何人都请指导我完成此操作。 p> <？xml version ='1.0'encoding ='UTF-8'？>
<！ - 是：<？xml version =1.0encoding =UTF-8？> - >
< beans xmlns =http://www.springframework.org/schema/beans
xmlns：xsi =http://www.w3.org/2001/XMLSchema-instance
xmlns：p =http://www.springframework.org/schema/p
xmlns：context =http://www.springframework.org/schema/context
xmlns ：mvc =http://www.springframework.org/schema/mvc
xsi：schemaLocation =http://www.springframework.org/schema/beans
http：// www。 springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/ spring-context-4.0.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd >

<！ - bean id =propertyConfigurer
class =org.springframework.beans.factory.config.PropertyPlaceholderConfigurer
p：location =/ WEB-INF /jdbc.properties/>

< bean id =dataSource
class =org.springframework.jdbc.datasource.DriverManagerDataSource
p：driverClassName =$ {jdbc.driverClassName}
p：url =$ {jdbc.url}
p：username =$ {jdbc.username}
p：password =$ {jdbc.password}/ - >

<！ - 在这里加入持久性支持（jpa，hibernate等） - >

< / beans>


dispatcher-servlet.xml

 <？xml version ='1.0'encoding ='UTF-8'？> 
<！ - 是：<？xml version =1.0encoding =UTF-8？> - > 
< beans xmlns =http://www.springframework.org/schema/beans
 xmlns：xsi =http://www.w3.org/2001/XMLSchema-instance
 xmlns：p =http://www.springframework.org/schema/p
 xmlns：context =http://www.springframework.org/schema/context
 xmlns ：mvc =http://www.springframework.org/schema/mvc
 xsi：schemaLocation =http://www.springframework.org/schema/beans 
 http：// www。 springframework.org/schema/beans/spring-beans-4.0.xsd 
 http://www.springframework.org/schema/context 
 http://www.springframework.org/schema/context/ spring-context-4.0.xsd 
 http://www.springframework.org/schema/mvc 
 http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd > 
 
< bean class =org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping/> 
< context：component-scan base-package =com.controller/> 
< mvc：annotation-driven /> 
 
 
 <！ -   -  
大多数控制器将使用上面的ControllerClassNameHandlerMapping，但是
用于我们使用ParameterizableViewController的索引控制器，所以我们必须使用
为其定义明确的映射。 
  - > 
< bean id =urlMappingclass =org.springframework.web.servlet.handler.SimpleUrlHandlerMapping> 
< property name =mappings> 
<道具> 
< prop key =index.htm> indexController< / prop> 
< /道具> 
< / property> 
< / bean> 
 
< bean id =viewResolver
 class =org.springframework.web.servlet.view.InternalResourceViewResolver
p：prefix =/ WEB-INF / jsp / 
p：suffix =。jsp/> 
 
 <！ -   -  
索引控制器。 
  - > 
< bean name =indexController
 class =org.springframework.web.servlet.mvc.ParameterizableViewController
 p：viewName =index/> 
 
< / beans> 
  

hibernate.cfg.xml

 <？xml version =1.0encoding =UTF-8？> 
<！DOCTYPE hibernate-configuration PUBLIC -  // Hibernate / Hibernate Configuration DTD 3.0 // ENhttp://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd\"> 
< hibernate-configuration> 
< session-factory> 
< property name =hibernate.connection.driver_class> oracle.jdbc.OracleDriver< / property> 
< property name =hibernate.connection.username> scott< / property> 
< property name =hibernate.connection.password> tiger< / property> 
< property name =hibernate.connection.url> jdbc：oracle：thin：@localhost：1521：orcl< / property> 
< property name =hibernate.current_session_context_class>线程< / property> 
< mapping resource =com / entity / EmpTest.hbm.xml/> 
< / session-factory> 
< / hibernate-configuration> 
  

EmpModelImpl.java

  / * 
 *要更改此许可证标题，请在项目属性中选择许可证标题。 
 *要更改此模板文件，请选择工具|模板
 *并在编辑器中打开模板。 
 * / 
 package com.model; 
 
 import com.entity.EmpTest; 
 import com.util.HibernateUtil; 
 import java.math.BigDecimal; 
 import java.util.List; 
 import org.hibernate.SessionFactory; 
 import org.springframework.stereotype.Repository; 
 
 
 @Repository 
 public class EmpModelImp {
 
 
 private SessionFactory session; 
 
 public void add（EmpTest emp）{
 session = HibernateUtil.getSessionFactory（）; 
 session.getCurrentSession（）。save（emp）; //抛出新的UnsupportedOperationException（暂不支持。 //要更改生成方法的主体，请选择工具|模板。 
 
 
 
 public void updateEmp（EmpTest emp）{
 session = HibernateUtil.getSessionFactory（）; 
 session.getCurrentSession（）。update（emp）; //抛出新的UnsupportedOperationException（还不支持。 //要更改生成方法的主体，请选择工具|模板。 
 
 
 
 public void delete（BigDecimal EmpId）{
 session = HibernateUtil.getSessionFactory（）; 
 session.getCurrentSession（）。delete（getEmp（EmpId））; // throw new UnsupportedOperationException（Not supported yet。）; //要更改生成方法的主体，请选择工具|模板。 
 
 
 
 public EmpTest getEmp（BigDecimal EmpId）{
 session = HibernateUtil.getSessionFactory（）; 
 return（EmpTest）session.getCurrentSession（）。get（EmpTest.class，EmpId）; // // new new UnsupportedOperationException（Not supported yet。）; //要更改生成方法的主体，请选择工具|模板。 
} 
 
 
公开列表< EmpTest> getAll（）{
 session = HibernateUtil.getSessionFactory（）; 
 return session.getCurrentSession（）。createCriteria（from emptest）。list（）; //抛出新的UnsupportedOperationException（还不支持。）; //要更改生成方法的主体，请选择工具|模板。 
} 
 
} 
  

EmpServiceImpl.java

  / * 
 *要更改此许可证标题，请在项目属性中选择许可证标题。 
 *要更改此模板文件，请选择工具|模板
 *并在编辑器中打开模板。 
 * / 
 package com.model; 
 
 import com.entity.EmpTest; 
 import java.math.BigDecimal; 
 import java.util.List; 
 import org.springframework.stereotype.Service; 
 import org.springframework.transaction.annotation.Transactional; 
 
 @Service 
 public class EmpServiceImpl {
 private EmpModelImp dao; 
 
 public EmpServiceImpl（）{
 this.dao = new EmpModelImp（）; 
} 
 @Transactional 
 public void add（EmpTest emp）{
 dao.add（emp）; 
} 
 
 @Transactional 
 public void updateEmp（EmpTest emp）{
 dao.updateEmp（emp）; 
} 
 
 @Transactional 
 public void delete（BigDecimal EmpId）{
 dao.delete（EmpId）; 
} 
 
 @Transactional 
 public EmpTest getEmp（BigDecimal EmpId）{
 return dao.getEmp（EmpId）; 
} 
 
 @Transactional 
 public List< EmpTest> getAll（）{
 return dao.getAll（）; 
} 
} 
  

我收到以下异常。

  org.hibernate.HibernateException：如果没有活动事务，createCriteria无效
 org.hibernate.context.internal.ThreadLocalSessionContext $ TransactionProtectionWrapper.invoke （ThreadLocalSessionContext.java:352）
 com.sun.proxy。$ Proxy98.createCriteria（Unknown Source）
 com.model.EmpModelImp.getAll（EmpModelImp.java:51）
 com.model .EmpServiceImpl.getAll（EmpServiceImpl.java:47）
  

解决方案

您需要开始和结束交易。

 会话会话= HibernateUtil.getSessionFactory（）。getCurrentSession（）; 
 session.beginTransaction（）; 
 EmpTest empTest =（EmpTest）session.get（EmpTest.class，EmpId）; 
 session.getTransaction（）。commit（）; 
  

您当然可以要求spring为您执行事务管理。但为此，您需要配置额外的transactionmanager bean。

I'm learning Spring 4.0 + Hibernate 4.3 integration and I'm very new to both technologies. I'm getting errors after solving previous. Anyone please guide me to complete this successfully.

applicationContext.xml

<?xml version='1.0' encoding='UTF-8' ?>
<!-- was: <?xml version="1.0" encoding="UTF-8"?> -->
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:p="http://www.springframework.org/schema/p"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:mvc="http://www.springframework.org/schema/mvc"
       xsi:schemaLocation="http://www.springframework.org/schema/beans 
       http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
       http://www.springframework.org/schema/context 
       http://www.springframework.org/schema/context/spring-context-4.0.xsd
       http://www.springframework.org/schema/mvc 
       http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd">

    <!--bean id="propertyConfigurer"
          class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"
          p:location="/WEB-INF/jdbc.properties" />

<bean id="dataSource"
    class="org.springframework.jdbc.datasource.DriverManagerDataSource"
    p:driverClassName="${jdbc.driverClassName}"
    p:url="${jdbc.url}"
    p:username="${jdbc.username}"
    p:password="${jdbc.password}" /-->

    <!-- ADD PERSISTENCE SUPPORT HERE (jpa, hibernate, etc) -->

</beans>

dispatcher-servlet.xml

<?xml version='1.0' encoding='UTF-8' ?>
<!-- was: <?xml version="1.0" encoding="UTF-8"?> -->
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:p="http://www.springframework.org/schema/p"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:mvc="http://www.springframework.org/schema/mvc"
       xsi:schemaLocation="http://www.springframework.org/schema/beans 
       http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
       http://www.springframework.org/schema/context 
       http://www.springframework.org/schema/context/spring-context-4.0.xsd
       http://www.springframework.org/schema/mvc 
       http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd">

    <bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>
    <context:component-scan base-package="com.controller"/>
    <mvc:annotation-driven />


    <!--
    Most controllers will use the ControllerClassNameHandlerMapping above, but
    for the index controller we are using ParameterizableViewController, so we must
    define an explicit mapping for it.
    -->
    <bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
        <property name="mappings">
            <props>
                <prop key="index.htm">indexController</prop>
            </props>
        </property>
    </bean>

    <bean id="viewResolver"
          class="org.springframework.web.servlet.view.InternalResourceViewResolver"
          p:prefix="/WEB-INF/jsp/"
          p:suffix=".jsp" />

    <!--
    The index controller.
    -->
    <bean name="indexController"
          class="org.springframework.web.servlet.mvc.ParameterizableViewController"
          p:viewName="index" />

</beans>

hibernate.cfg.xml

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
  <session-factory>
    <property name="hibernate.connection.driver_class">oracle.jdbc.OracleDriver</property>
    <property name="hibernate.connection.username">scott</property>
    <property name="hibernate.connection.password">tiger</property>
    <property name="hibernate.connection.url">jdbc:oracle:thin:@localhost:1521:orcl</property>
    <property name="hibernate.current_session_context_class">thread</property>
    <mapping resource="com/entity/EmpTest.hbm.xml"/>
  </session-factory>
</hibernate-configuration>

EmpModelImpl.java

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
package com.model;

import com.entity.EmpTest;
import com.util.HibernateUtil;
import java.math.BigDecimal;
import java.util.List;
import org.hibernate.SessionFactory;
import org.springframework.stereotype.Repository;


@Repository
public class EmpModelImp {


   private SessionFactory session;

    public void add(EmpTest emp) {
       session=HibernateUtil.getSessionFactory();
       session.getCurrentSession().save(emp);// throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
    }


    public void updateEmp(EmpTest emp) {
        session=HibernateUtil.getSessionFactory();
       session.getCurrentSession().update(emp);//  throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
    }


    public void delete(BigDecimal EmpId) {
     session=HibernateUtil.getSessionFactory();
        session.getCurrentSession().delete(getEmp(EmpId));// throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
    }


    public EmpTest getEmp(BigDecimal EmpId) {
        session=HibernateUtil.getSessionFactory();
        return (EmpTest) session.getCurrentSession().get(EmpTest.class, EmpId);// //throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
    }


    public List<EmpTest> getAll() {
        session=HibernateUtil.getSessionFactory();
       return session.getCurrentSession().createCriteria("from emptest").list(); //throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
    }

}

EmpServiceImpl.java

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
package com.model;

import com.entity.EmpTest;
import java.math.BigDecimal;
import java.util.List;
import org.springframework.stereotype.Service;
import org.springframework.transaction.annotation.Transactional;

@Service
public class EmpServiceImpl {
 private EmpModelImp dao;   

    public EmpServiceImpl() {
        this.dao = new EmpModelImp();
    }
    @Transactional
    public void add(EmpTest emp) {
        dao.add(emp);
    }

    @Transactional
    public void updateEmp(EmpTest emp) {
        dao.updateEmp(emp);
    }

    @Transactional
    public void delete(BigDecimal EmpId) {
        dao.delete(EmpId);
    }

    @Transactional
    public EmpTest getEmp(BigDecimal EmpId) {
        return dao.getEmp(EmpId);
    }

    @Transactional
    public List<EmpTest> getAll() {
        return dao.getAll();
    }
}

I'm getting following exception.

org.hibernate.HibernateException: createCriteria is not valid without active transaction
    org.hibernate.context.internal.ThreadLocalSessionContext$TransactionProtectionWrapper.invoke(ThreadLocalSessionContext.java:352)
    com.sun.proxy.$Proxy98.createCriteria(Unknown Source)
    com.model.EmpModelImp.getAll(EmpModelImp.java:51)
    com.model.EmpServiceImpl.getAll(EmpServiceImpl.java:47)

解决方案

You need to begin and end the transaction as well.

        Session session = HibernateUtil.getSessionFactory().getCurrentSession();
        session.beginTransaction();
       EmpTest empTest = (EmpTest) session.get(EmpTest.class, EmpId);
        session.getTransaction().commit();

You can of course ask spring to do the transaction management for you. But for that you need to configure additional transactionmanager bean.

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