两个派,一个传奇与独特的项目(合并传说) [英] Two pies, one legend with unique items (merge legends)

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问题描述

是否可以在一个图形中合并两个饼图并合并传说?



我这样做了: http://jsfiddle.net/Adysone/YpfBs/

  chart = new Highcharts.Chart({
图表:{
renderTo:'container',
type:'pie'
},
title:{
文字:饼图,
align:'center'
},
图例:{
layout:'vertical',
align:'right',
verticalAlign:'top'
},
tooltip:{
formatter:function(){
return this.key +':'+ this.y +' ('+ Math.round(this.percentage)+'%)';
}
},
plotOptions:{
pie:{
showInLegend:true,
size:200
}
},
series:[
{
名称:2011,
dat a:[
{
name:Apple,
color:#FF3333,
y:8
},
{
名称:香蕉,
颜色:#FFF55C,
y:11
},
{
名称:葡萄,
颜色: #90007B,
y:9
},
{
名称:梨,
颜色:#F1FFB8,
y:3


中心$ 150,100 b $ b大小150


名称2012,
data:[
{
name:Apple,
color:#FF3333,
y:5
},
{
名称:香蕉,
颜色:#FFF55C,
y:15
},
{
名称:Pear,
颜色:#F1FFB8,
y:8
}
],
中心:[450,100],
大小:150
}
]
});

但传说中的项目是重复的,因为它们在两个派中很常见,我该怎么做才能做到这些如果这是不可能的,我可以让两个传说分开吗?



谢谢!

解决方案

请看例子 http:// jsfiddle .net / u7FQS / 15 / 使用3个饼图并具有常见图例

  $(chart.series [ 0] .data).each(function(i,e){
e.legendItem.on('click',function(event){
var legendItem = e.name;

event.stopPropagation();

$(chart.series).each(function(j,f){
$(this.data).each(function(k, z){
if(z.name == legendItem)
{
if(z.visible)
{
z.setVisible(false);
}
else
{
z.setVisible(true);
}
}
});
});

});
});


Is it possible to do two pies in one graphic and merge legends?

I did this : http://jsfiddle.net/Adysone/YpfBs/

chart = new Highcharts.Chart({
    chart: {
        renderTo: 'container',
        type: 'pie'
    },
    title: {
        text: "Pie Charts",
        align: 'center'
    },
    legend: {
        layout: 'vertical',
        align: 'right',
        verticalAlign: 'top'
    },
    tooltip: {
        formatter: function () {
            return this.key + ': ' + this.y + ' (' + Math.round(this.percentage) + '%)';
        }
    },
    plotOptions: {
        pie: {
            showInLegend: true,
            size: 200
        }
    },
    series: [
        {
            name: "2011",
            data: [
                {
                    name: "Apple",
                    color: "#FF3333",
                    y: 8
                },
                {
                    name: "Banana",
                    color: "#FFF55C",
                    y: 11
                },
                {
                    name: "Grape",
                    color: "#90007B",
                    y: 9
                },
                {
                    name: "Pear",
                    color: "#F1FFB8",
                    y: 3
                }
            ],
            center: [150,100],
            size: 150
        },
        {
            name: "2012",
            data: [
                {
                    name: "Apple",
                    color: "#FF3333",
                    y: 5
                },
                {
                    name: "Banana",
                    color: "#FFF55C",
                    y: 15
                },
                {
                    name: "Pear",
                    color: "#F1FFB8",
                    y: 8
                }
            ],
            center: [450,100],
            size: 150
        }
    ]
});

But legend items are duplicated since they are common in the two pies, how can I do to make these unique?

If it's not possible, can I make two legends separate?

Thanks!

解决方案

Please take look at example http://jsfiddle.net/u7FQS/15/ which used 3 pie charts and has common legend

$(chart.series[0].data).each(function(i, e) {
        e.legendItem.on('click', function(event) {
            var legendItem=e.name;

            event.stopPropagation();

            $(chart.series).each(function(j,f){
                   $(this.data).each(function(k,z){
                       if(z.name==legendItem)
                       {
                           if(z.visible)
                           {
                               z.setVisible(false);
                           }
                           else
                           {
                               z.setVisible(true);
                           }
                       }
                   });
            });

        });
    });

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